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3 years ago

John's test grades are 69, 86, 100, and 105. What is his average?

Mathematics

2 answers:

Lunna [17]3 years ago

8 0

The answer is 90. you add them all up and divide it by 4

daser333 [38]3 years ago

8 0

Answer: John’s average test score is 90.

Step-by-step explanation:

To find the average of a set of numbers, we must find the sum of all of the numbers (add them together) and then divide by the amount of numbers in the set. In this case, we begin by finding the sum of the four numbers:

69 + 86 + 100 + 105

= 360

Then, we divide by 4, since there are 4 scores in the data set.

360/4 = 90

Therefore, John’s average test score is 90.

Hope this helps!

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4 years ago

Read 2 more answers

B is the midpoint of AC, E is the midpoint of BD. If A(-9,-4), C(-1,6), and E(-4,-3), find the coordinates of D

Vadim26 [7]

Answer:

(-3, -7)

Step-by-step explanation:

Let $(x_{A,}y_{A}),(x_{B},y_{B}),(x_{C,}y_{C}),(x_{D,}y_{D})(x_{E,}y_{E)} \text{be the coordinates of points A, B, C respectively}\\\\$

The midpoint coordinates $(x_{M},y_{M})$ of any two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ are given by $x_{M}=\frac{(x_{1}+x_{2)}}{2}$ and $y_{M}=\frac{y_{1}+y_{2}}{2}$

Since B is the midpoint of AC

$x_{B}=\frac{(x_{A}+x_{C})}{2}=\frac{(-9+(-1)}{2}=\frac{-9-1}{2}=\frac{-10}{2}=-5$

$y_{B}=\frac{(y_{A}+y_{C})}{2}=\frac{(-4+6)}{2}=\frac{2}{2}=1$

Since E is the midpoint of B and D and we are given the coordinates of E as (-4,-3). it follows that

$x_{E}=\frac{x_{B}+x_{D}}{2} = \frac{-4+x_{D}}{2}$

Therefore

$x_{D}=2x_{E}+4=2(-5)+4=-3$

Similarly

$y_{E}=\frac{y_{B}+y_{D}}{2} = \frac{1+x_{D}}{2}y_{D}=2y_{E}-1=2(-3)-7=-7$

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2 years ago

Let U = {q, r, s, t, u, v, w, x, y, z} A = {q, s, u, w, y} B = {q, s, y, z} C = {v, w, x, y, z}. List the elements in the set: A

gtnhenbr [62]

Answer:

$A \cup C=\left \{ \text{q, s, u, v, w, x, y, z} \right \}$

Step-by-step explanation:

Given: $\text{U}=\left \{\text{q, r, s, t, u, v, w, x, y, z} \right \}$ , $\text{A}=\left \{\text{q, s, u, w, y} \right \}$ , $\text{B}=\left \{\text{q, s, y, z} \right \}$ ,