Three consecutive even integers can be represented by x, (x+2), and (x+4).
(x + (x + 2) + (x + 4)) - 10 = -22 Get rid of the parentheses
x + x + 2 + x + 4 - 10 = -22 Combine like terms (x + x + x) and (2 + 4 - 10)
3x - 4 = -22 Add 4 to both sides
3x = -18 Divide
x = -6
Check you work.
x = -6
x + 2 = -4
x + 4 = -2
(-6 - 4 - 2) - 10 = 22
-12 - 10 = -22
So, your three integers are -6, -4, and -2 .
Let's evaluate ~
The given expression is :
plug the value of x as 3
Therefore, the required value is 20
Cos(A-B) = cosAcosB + sinAsinB
<span>
cos(</span>π/2 - θ) = cos(π/2)cosθ + sin(π/2)sinθ
π/2 = 90°
cos(π/2) = cos90° = 0. sin(π/2) = sin90° = 1
cos(π/2 - θ) = cos(π/2)cosθ + sin(π/2)sin<span>θ
</span>
= 0*cosθ + 1*sin<span>θ = </span>sin<span>θ
Therefore </span>cos(π/2 - θ) = sin<span>θ
QED </span>
Answer:
image attached
Step-by-step explanation:
