Answer:
16 factors
Step-by-step explanation:
I hope this helps
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The value of x in x^yz = y^2 is ![x = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
<h3>How to solve for x?</h3>
The equation is given as:
x^yz = y^2
Rewrite the equation properly as follows
Take the yz root of both sides
![\sqrt[yz]{x^{yz}} = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=%5Csqrt%5Byz%5D%7Bx%5E%7Byz%7D%7D%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Apply the law of indices
![x^{\frac{yz}{yz}} = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Byz%7D%7Byz%7D%7D%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Divide yz by yz
Hence, the value of x in x^yz = y^2 is
Read more about equations at:
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Here, we are required to determine the point where point H lie on the number line.
The point H is at point 2.5 on the number line.
The distance between point F and G on the number line is:
4 - (-2) = 6 numbers on the number line.
And since the ratio of FH to HG is 3:9
- Then, let point H be at no. X on the number line.
Therefore; FH/HG = (4 - x)/(x - (-2))
i.e 3/9 = (4 - x)/ (x +2).
By cross multiplication, 3x + 6 = 36 - 9x.
Therefore, 12x = 30
and, x = 2.5
Therefore, the point H is at point 2.5 on the number line.
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brainly.com/question/18329661
Get it to equal 0
minus 17x from both sides
2x²-17x+35=0
tricky part
get something like
(2x-a)(x-b)
we know the signs are negative since the middle term is negative and last term is positive
so a and b are either 1 and 35 or 5 and 7
(2x-1)(x-35), nope
(2x-35)(x-1) nope
(2x-5)(x-7), nope
(2x-7)(x-5), yep
(2x-7)(x-5)=0
set to zero
2x-7=0
2x=7
x=7/2
x-5=0
x=5
x=7/2 and 5
