Tape measure
thermometer measures temp
scale measures weight
clock measures time
tape measure measures length
Answer:
The answer would be B if im wrong SORRY ;)![\beta\beta \beta \beta \beta \beta \beta \beta \beta \beta \beta \beta \beta \beta \beta](https://tex.z-dn.net/?f=%5Cbeta%5Cbeta%20%5Cbeta%20%5Cbeta%20%5Cbeta%20%5Cbeta%20%5Cbeta%20%5Cbeta%20%5Cbeta%20%5Cbeta%20%5Cbeta%20%5Cbeta%20%5Cbeta%20%5Cbeta%20%5Cbeta)
Step-by-step explanation:
To make a box and whisker plot, first you write down all of the numbers from least to greatest.
0, 1, 3, 4, 7, 8, 10
The median is 4, so that’s the middle line of the plot.
So now we have:
0, 1, 3, [4,] 7, 8, 10
So next we have to find the 1st and 3rd interquartiles..
0, [1,] 3, [4,] 7, [8,] 10
Those are the next 2 points you put on the plot.
Lastly, the upper and lower extremes. These are the highest and lowest numbers in the data.
[0,] 1, 3, 4, 7, 8, [10]
These are the final points on the plot.
To make the box of a box-and-whisker plot, you plot the 3 Medians of the data: 1, 4, and 8, and connect those to make a box that has a line in the middle at 4.
Next, you plot the upper and lower extremes: 0 and 10, by making “whiskers” that connect to the box. So you draw a line from the extremes to the box.
Is that supposed to be x² -4x -5 = 0 or x²-4-5=0 as written? We'll do both.
As written it's
x²=9 so x=±3, no quadratic formula required.
Let's assume you meant
x² -4x - 5 = 0
So much temptation. This factors as
(x-5)(x+1)=0 so roots x=5, x=-1. But that didn't use the quadratic formula..
There's a shortcut to the quadratic formula called the Shakespeare Quadratic Formula (2b or -2b) that's useful when the linear term is even.
In that case x²-2bx+c has zeros at z=b±√(b²-c)
x = 2 ± √(4 - -5) = 2 ± √9 = 2 ± 3 = { -1 , 5 }
OK, let's do it like they want
x² - 4x - 5 = 0
We have a=1, b=-4, c=-5 and the quadratic formula
![x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B-b%20%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
![x = \dfrac{-(-4) \pm \sqrt{(-4)^2-4(1)(-5)}}{2(1)} = \frac 1 2 (4 \pm \sqrt{36}) = \frac 1 2 (4 \pm 6) = \{-1, 5\}](https://tex.z-dn.net/?f=x%20%3D%20%5Cdfrac%7B-%28-4%29%20%5Cpm%20%5Csqrt%7B%28-4%29%5E2-4%281%29%28-5%29%7D%7D%7B2%281%29%7D%20%3D%20%5Cfrac%201%202%20%284%20%5Cpm%20%5Csqrt%7B36%7D%29%20%3D%20%5Cfrac%201%202%20%284%20%5Cpm%206%29%20%3D%20%5C%7B-1%2C%205%5C%7D)
Answer: x=-1 or x=5