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sashaice [31]
1 year ago
13

PLS HELP WILL GET BRAINLIEST

Mathematics
1 answer:
Tatiana [17]1 year ago
4 0

Step-by-step explanation:

just look at the objects !

they are completely regular, and each arm can cover every other other arm.

so,

15A needs 1/3 of a full rotation.

15B needs 1/2 of a full rotation.

15C needs 1/4 of a full rotation.

15D needs (can you guess ?) ... 1/6 of a full rotation.

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Write the fraction in simple form 6/12
Mila [183]

Answer:

1/2

Step-by-step explanation:

6 is half of 12 so it would simplify to 1/2

5 0
3 years ago
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69.6% of all full-time law enforcement officers are sworn officers, and of those, 88.2% were males. Females, however, make up 60
Evgen [1.6K]

Answer:

The probability that he or she is a male or a civilian employee is 1.037068

Step-by-step explanation:

Probability of sworn officers = 0.696

Probability of civilians = 1 - 0.696 = 0.304

Probability of male sworn officers = 0.882*0.696 = 0.6139

Probability of male civilian = (0.304*(1-0.608)) = 0.1192

Hence probability that he or she is a male or civilian employee is

0.6139 + 0.1192 + 0.304 = 1.037068

7 0
3 years ago
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The mean percentange of a population of people eating out at least once a week is 57℅
Sidana [21]

Answer:

<u>The correct answer is B. between 56.45% and 57.55% </u>

Complete statement and question:

The mean percentage of a population of people eating out at least once a week is 57% with a standard deviation of 3.50%. Assume that a sample size of 40 people was surveyed from the population a significant number of times. In which interval will 68% of the sample means occur?

between 55.89% and 58.11%

between 56.45% and 57.55%

between 56.54% and 57.46%

between 56.07% and 57.93%

Source: brainly.com/question/1068489

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Mean percentage of a population of people eating out at least once a week  = 57%

Standard deviation = 3.5%

Sample size = 40

Confidence level = 68%

2. In which interval will 68% of the sample means occur?

For answering this question, we should find out the standard deviation of the sample, using this formula:

Standard deviation of the sample = Standard deviation of the population/√Sample size

Standard deviation of the sample = 3.5/√40

Standard deviation of the sample = 3.5/6.32

Standard deviation of the sample = 0.55

Let's recall that a confidence level of 68% means that 68% of the sample data would have a value between the mean - 1 time the standard deviation of the sample and the mean  + 1 time the standard deviation of the sample. Thus:

57 - 1 * 0.55 = 57 - 0.55 = 56.45

57 + 1  * 0.55 = 57 + 0.55 = 57.55

<u>The correct answer is B. between 56.45% and 57.55% </u>

7 0
3 years ago
Find the x and y intercepts of the graph of the function
Mkey [24]

Answer:

y intercepts= 0       x intercepts= none

nation:

The 2 funtions above the x axis do not intercept with the y-axis or the x-axis. They just hover above it, but never atcually touch it.

The function bellow the x-axis only intercepts the y-axis at 0,0

8 0
2 years ago
The school play earned $11,271 in ticket sales. If the cost of each ticket was $13, how many tickets were sold?
mojhsa [17]

Answer:

867 tickets were sold because if you divide how much they earned by how much it cost you get 867

8 0
3 years ago
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