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soldier1979 [14.2K]
3 years ago
7

Solve x + 3y = 9 3x – 3y = -13 (1 point)

Mathematics
1 answer:
Mariana [72]3 years ago
8 0

Answer:

The values of x and y to the given equations are x=-1 and y=\frac{10}{3}

The solution is (-1,\frac{10}{3})

Step-by-step explanation:

Given equations are x+3y=9\hfill (1)

and 3x-3y=-13\hfill (2)

to solve the given equations by elimination method :

Adding the given two equations (1) and (2) we get

x+3y=9

3x-3y=-13

_______________

4x=-4

x=-\frac{4}{4}

Therefore x=-1

Now substitute the value x=-1 in equation(1) we get

(-1)+3y=9

3y=9+1

y=\frac{10}{3}

Therefore the values of x and y to the given equations are x=-1 and y=\frac{10}{3}

The solution is (-1,\frac{10}{3})

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Write the line (-5,-6) with slope 2/5 in point-slope form
stich3 [128]

Answer:

y+6=\frac{2}{5} (x+5).

Step-by-step explanation:

1) the common form of the point-slope form is y-y₁=s(x-x₁), where s - the slope, (x₁;y₁) - the point belongs to the required line;

2) if s=2.5; x₁= -5; y₁= -6, then the required equation is:

y+6=2/5(x+5).

5 0
3 years ago
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tamaranim1 [39]

Answer:

44, 6, and 24 are not perfect square

Step-by-step explanation:

Perfect square are numbers that can be square rooted with a result of a perfect whole number.

√16=4

√44= 6.63324...

√81= 9

√6= 2.44948...

√49= 7

√24= 4.898997...

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2 years ago
A recipe for chili calls for 5 pounds of ground beef for 18 people. How many pounds of ground beef are needed for 50 people
tatyana61 [14]
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Set up the proportion 5/18 = x/50 18x=250 Solve for x
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3 years ago
Abc=3x+5 cbd=2x+5 find the following m
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Suppose the half-life of a material is 10 days. You have one 1 kg of the material today. How much of the material would you have
boyakko [2]

Answer:

0.50 kg of the material would be left after 10 days.

0.25 kg of the material would be left after 20 days.

Step-by-step explanation:

We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after  10 days and 20 days, respectively.

We will use half life formula.

A=a\cdot(\frac{1}{2})^{\frac{t}{h}}, where,

A = Amount left after t units of time,

a = Initial amount,

t = Time,

h = Half-life.

A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{10}{10}}

A=1\text{ kg}\cdot(\frac{1}{2})^{1}

A=1\text{ kg}\cdot\frac{1}{2}

A=0.5\text{ kg}

Therefore, amount of the material left after 10 days would be 0.5 kg.

A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{20}{10}}

A=1\text{ kg}\cdot(\frac{1}{2})^{2}

A=1\text{ kg}\cdot\frac{1^2}{2^2}

A=1\text{ kg}\cdot\frac{1}{4}

A=0.25\text{ kg}

Therefore, amount of the material left after 20 days would be 0.25 kg.

6 0
3 years ago
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