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3 years ago

9

How to classify 17/10

2 answers:

Zarrin [17]3 years ago

7 0

Real numbers encompass three classifications of numbers, which we'll talk about in a little bit. Whole numbers, rational numbers, and irrational numbers are all real numbers. Imaginary numbers are not real numbers. They are complex numbers that are written as a real number multiplied by an imaginary unit (

storchak [24]3 years ago

4 0

Answer:

rational

Step-by-step explanation:

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Find the decimal that is equivalent to <br> 1/15?

aleksley [76]

0.0667
Hope this helpsss

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2 years ago

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What is 1+1 . i apparently have to write 20 characters so here they are

Liula [17]

Answer:

2

Step-by-step explanation:

8 0

3 years ago

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John's dog eats 8 ounces of dog food each day. John bought 20-pound bag of dog food. How many 8 - ounces are in 28- pounds of do

aleksley [76]

8x3= 24...
there are 3 8 ounces in 28 pounds of dog food...
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3 years ago

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What is the distance from the point (a, −b, −4) to the origin?

laiz [17]

Answer:

$\sqrt{a^2+b^2+16}$

Step-by-step explanation:

The distance (d) between two points in 3 dimensions is ...

d = √((x2 -x1)² +(y2 -y1)² +(z2 -z1)²)

Then the distance between (a, -b, -4) and (0, 0, 0) is ...

d = √((a -0)² +(-b -0)² +(-4 -0)²)

= √(a² +b² +16)

6 0

3 years ago

Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '[infinity]' or

soldi70 [24.7K]

Answer:

The limit of this function does not exist.

Step-by-step explanation:

$\lim_{x \to 3} f(x)$

$f(x)=\left \{ {{9-3x} \quad if \>{x \>< \>3} \atop {x^{2}-x }\quad if \>{x\ \geq \>3 }} \right.$

To find the limit of this function you always need to evaluate the one-sided limits. In mathematical language the limit exists if

$\lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) =L$

and the limit does not exist if

$\lim_{x \to a^{-}} f(x) \neq \lim_{x \to a^{+}} f(x)$

Evaluate the one-sided limits.

The left-hand limit

$\lim_{x \to 3^{-} } 9-3x= \lim_{x \to 3^{-} } 9-3*3=0$

The right-hand limit

$\lim_{x \to 3^{+} } x^{2} -x= \lim_{x \to 3^{+} } 3^{2}-3 =6$

Because the limits are not the same the limit does not exist.

8 0

3 years ago