Answer:
48 cm
Step-by-step explanation:
Given:
Distance of rod from the wall = 45 cm
Distance of rod from the light = 15 cm
Length of rod = 12 cm
We can see that <DAM and <BAF are equal
Also, <DMA and <BFM are equal because they are corresponding angles
To find the length of the shadow, let's take the equation

Where.:
DM = ½ of length of the rod = ½*12 = 6
A.F = 15 + 45 = 60 cm
AM = 15 cm
Therefore,


Cross multiplying, we have:
15 * B.F = 60 * 6
15 * B.F = 360

BF = 24 cm
The shadow on the wall =
2 * BF
= 2 * 24
= 48 cm
The shadow on the wall is 48 cm
Answer:
Hence, the cubic root of 32768 by the method of prime factorization comes out to be 32
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Answer:
The median for Springwood is 86 and the median for Meadows is 73. The interquartile range for Springwood is 14. The interquartile range of Meadows is 12.
Step-by-step explanation:
The median is the middle line of a box plot. The interquartile range is the is third quartile minus the first quartile.