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Bond [772]
3 years ago
6

State which measure of center, or measure of spread, represents the situation. A company finds the difference between the lighte

st and the heaviest packages it ships.
Mathematics
1 answer:
bearhunter [10]3 years ago
8 0
The difference between the minimum data point and the maximum data point is called the range. This is a measure of spread.
Other measures of spread include the interquartile range/IQR, which helps eliminate outliers, the standard deviation, and the mean absolute deviation. Measures of central tendency include the mean, median & mode.

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How do I know whether something is a function or not? Answer the worksheet please
djyliett [7]
Because you if it changes its a function
6 0
3 years ago
Plz help me quick!!!!!!!!!!!!!!!!!!!!!!!!
beks73 [17]

Answer:

Exact Form: 5/2

Decimal Form: 2.5

Mixed Number Form: 2 1/2

Step-by-step explanation:

5 0
3 years ago
-1/3 + (-7/4)<br> pls help
djverab [1.8K]

Answer:

  -25            

 ——— = -2.08333

    12  

Step-by-step explanation:

Step  1  :

           7

Simplify   —

           4

Equation at the end of step  1  :

       1           7

 (0 -  —) +  (0 -  —)

       3           4

Step  2  :

           1

Simplify   —

           3

Equation at the end of step  2  :

       1     -7

 (0 -  —) +  ——

       3     4

Step  3  :

Calculating the Least Common Multiple :

3.1    Find the Least Common Multiple

     The left denominator is :       3

     The right denominator is :       4

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

3 1 0 1

2 0 2 2

Product of all

Prime Factors  3 4 12

     Least Common Multiple:

     12

Calculating Multipliers :

3.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 4

  Right_M = L.C.M / R_Deno = 3

Making Equivalent Fractions :

3.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      -1 • 4

  ——————————————————  =   ——————

        L.C.M               12  

  R. Mult. • R. Num.      -7 • 3

  ——————————————————  =   ——————

        L.C.M               12  

Adding fractions that have a common denominator :

3.4       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

-1 • 4 + -7 • 3     -25

———————————————  =  ———

      12            12

Final result :

 -25            

 ——— = -2.08333

 12            

Processing ends successfully

plz mark me as brainliest :)

7 0
3 years ago
Read 2 more answers
What is the quotient of -8(^6)/4x(^-3)
Anna [14]

For this case we must find the quotient of the following expression:

\frac {-8x ^ 6} {4x ^ {- 3}} =

By definition of power properties we have:

a ^ {- 1} = \frac {1} {a ^ 1} = \frac {1} {a}

Rewriting the expression we have:

\frac{-8}{4}*x^6*x^3

By definition of multiplication of powers of the same base we have to put the same base and add the exponents:

-2x^{6+3}

Answer:

-2x ^ 9

8 0
3 years ago
A line passes through the points (–1, –5) and (4, 5). The point (a, 1) is also on the line.
IgorC [24]

Answer:

a = 2

Step-by-step explanation:

Let's find the equation of the line using the 2 points given.

Let's call -1 as x_1 and -5 as y_1

also, 4 as x_2 and 5 as y_2

The equation of line is :

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

<em>Let's plug the points and get the equation of the line:</em>

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\y+5=\frac{5+5}{4+1}(x+1)\\y+5=2(x+1)\\y+5=2x+2\\y=2x-3

Now, to find a, we substitute a in x and 1 in y of the equation of the line we just got:

y=2x-3\\1=2(a)-3\\1=2a-3\\2a=4\\a=\frac{4}{2}=2

4 0
3 years ago
Read 2 more answers
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