A: Suppose Mr. Moore decides to use 20 seventh graders as the sample. Is this sample a random sample? Explain your reasoning.
Ans: No, because he only chose the seventh graders which is invalid since he wants to have to use the mean height which involves the 6th, 7th and 8th graders.
B: Mr. Moore decides to use a random number generator to select 20 students from the school. Suppose that when choosing 20 students using the random generator on the graphing calculator, Mr. Moore’s sample is all eighth graders. Does that mean the sample is not a random sample? Explain your reasoning.
Ans: No, it is still a random sample. Since he is using a random generator, there is a possibility that the random generator would pick all students from the 8th grade. Unlike the first one, the random generator is not biased towards any grade, it is just a coincidence.
Answer:
15
Step-by-step explanation:
Answer:
parallelogram
Step-by-step explanation:
The computation shows that the voter is the first to receive both items is A. the 42nd voter.
<h3>How to compute the value?</h3>
From the information, the candidates running for office are handing out items to voters as every 6th voter gets a button while every 7th voter gets a sticker.
Therefore, it should be noted that the least common multiple of both 6 and 7 is 42. Therefore, the voter is the first to receive both items is the 42nd voter.
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The statements that aer true or not or whatever
hmm, let's try te sencnarios
remember the commutative property of multiplication
ab=ba
so
what if they are both negative?
well, the negatives would cancel to leave with positive
the oposite would be both positive resulting in a positive
if they are differnt signs then result is negative
oposite would be still different signs so still negative
true statment