Answer:
5
Step-by-step explanation:
Answer:
3.21 grams
Step-by-step explanation:
First we are finding the radioactive decay constant using the formula:
lambda = 
where
lambda is the radioactive decay constant.
is the half life of the radioactive substance.
We know from our problem that Rutherfordium- 265 has a half-life of 13 hours, so let's replace the value in our formula.
lambda = 
lambda = 0.0533 per hour
Now we can use the decay formula to find the remaining quantity of the substance:

where
is the ending amount
is the beginning amount
is the time (in hours)
We know from our problem that there is a 149g sample of Rutherfordium- 265 left at 12am on October 19th, so
. Notice that there are exactly 3 days from 12 am October 19th to 12 am October 22nd, so we have
; therefore
. Now we can replace all the values in our formula:


We can conclude that 3.21 grams of Rutherfordium- 265 would remain on October 22nd at 12 am.
Answer:
72 houses.
Step-by-step explanation:
We are told that a postal worker can deliver the mail to 18 houses in 15 minutes.
Let us find numbers of mails delivered by postal worker per minute.


Since we know that 1 hour equals 60 minutes, so we will multiply 1.2 by 60 to find the number mails postal worker will deliver in 1 hour.


Therefore, the postal worker will be able to deliver mails to 72 houses in 1 hour.