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GalinKa [24]
3 years ago
9

#27 would you try different t values to find H? Or not?

Mathematics
1 answer:
maks197457 [2]3 years ago
6 0

H=H(t) represents the number of households that own ...blah... t years 1996. So H(0) is the number of households in the year 1996; we're told that H(0)=62 (since H is the number of households in millions).

At the end of each year, this number increases by 4.85%, i.e. a factor of 1.0485. This means after 1 year, the number of households is

H(1)=1.0485H(0)\approx65

After 2 years, or 1 year after the first year elapses, the number is

H(2)=1.0485H(1)=1.0485^2H(0)\approx68

After 3 years,

H(3)=1.0485H(2)=1.0485^3H(0)\approx71

and so on, with the general pattern of

H(t)=1.0485^tH(0)\implies\boxed{H(t)=62\cdot1.0485^t}

This is the function you're asked to find.

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1,600,000,000 / 31,536,000 

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hope this helps
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3 years ago
Point A lies outside of plane P. How many lines can be drawn perpendicular to plane P through point A?
Ivanshal [37]

<em>Answer</em>


D) 1


<em>Explanation</em>

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If a line is to be drawn from a point to a line or a plain it can only be one. In this case a line is to be drawn through a point A to a plane P. If the line is to be perpendicular, then is is only one.


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3 0
2 years ago
Read 2 more answers
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3 0
3 years ago
Simplify this problem
ikadub [295]

Answer:

\boxed{  \frac{ \sqrt[3]{ {x}^{11} } }{4} }

Step-by-step explanation:

=  >  \frac{ {x}^{4} }{ \sqrt[3]{64x} }  \\  \\  =  >  \frac{ {x}^{4} }{ {(64x)}^{ \frac{1}{3} } }  \\  \\  =  >  \frac{ {x}^{4} }{ ({64}^{ \frac{1}{3} }  )\times  ({x}^{ \frac{1}{3} } )}  \\  \\  =  >  \frac{ {x}^{4} }{ ({( {4}^{3} )}^{ \frac{1}{3} }) \times(  {x}^{ \frac{1}{3} }  )}  \\  \\  =  >   \frac{ {x}^{4} }{ ({4}^{ \cancel{3} \times  \frac{1}{ \cancel{3}} } ) \times(  {x}^{ \frac{1}{3} }  )}   \\  \\  =  >  \frac{ {x}^{4} }{4 {x}^{ \frac{1}{3} } }  \\  \\  =  >  \frac{ {x}^{4 -  \frac{1}{3} } }{4}  \\  \\  =  >  \frac{ {x}^{ \frac{12 - 1}{3} } }{4}  \\  \\  =  >  \frac{ {x}^{ \frac{11}{3} } }{4}  \\  \\  =  >   \frac{ \sqrt[3]{ {x}^{11} } }{4}

7 0
3 years ago
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