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rosijanka [135]
3 years ago
13

Item 20 A rectangular school banner has a length of 54 inches and a width of 36 inches. A sign is made that is similar to the sc

hool banner and has a length of 17 inches. What is the ratio of the area of the school banner to the area of the sign
Mathematics
2 answers:
siniylev [52]3 years ago
6 0

Answer:

The ratio of the area of the school banner to the area of the sign is <u>1944 cubic inches : 192.61 cubic inches.</u>

Step-by-step explanation:

Given:

A rectangular school banner has a length of 54 inches and a width of 36 inches. A sign is made that is similar to the school banner and has a length of 17 inches.

Now, to find the ratio of the area of the school banner to the area of the sign.

Dimensions of school banner :

Length = 54 inches.

Width = 36 inches.

Dimension of school sign:

Length = 17 inches.

So, to we find the width of sign by using cross multiplication method:

Let the width be x.

So, 54 is equivalent to 36.

Thus, 17 is equivalent to x.

\frac{54}{36} =\frac{17}{x}

By cross multiplying we get:

54x=612

Dividing both sides by 54 we get:

x=11.33\ inches.

Thus, the width of sign = 11.33 inches.

Now, to get the ratio of the area of the school banner to the area of the sign:

Area of the school banner : Area of the school sign.

= 54\times 36:17\times 11.33

= 1944:192.61

Therefore, the ratio of the area of the school banner to the area of the sign is 1944 cubic inches : 192.61 cubic inches.

erastova [34]3 years ago
4 0

Answer:

The ratio of the area of the school banner to the area of the sign is 1944 : 192.61.

Step-by-step explanation:

Given:

Length of the School banner (l_1) = 54 inches

width of the school banner (w_1) = 36 inches

Length of the sign (l_2) = 17 inches

We need to find the ratio of the area of the school banner to the area of the sign

Solution:

First we will find the width of the sign.

Let the width of the sign be w_2

Now we know that;

When two rectangles are similar to each other then their ratio of the dimension are equal.

so we can say that;

\frac{l_1}{l_2}=\frac{w_1}{w_2}\\\\\frac{54}{17}=\frac{36}{w_2}

By using Cross multiplication we get;

w_2=\frac{17\times36}{54} = 11.33\ in

Now we will find the Area.

Area of school banner is equal to length of the school banner times width of the school banner.

framing in equation form we get;

Area of school banner = 54\times36 = 1944 \ ft^2

Area of the sign is equal to length of the sign times width of the sign.

framing in equation form we get;

Area of the sign = 17\times11.33= 192.61\ ft^2

Now we will find the ratio of the area of the school banner to the area of the sign.

\frac{\textrm{Area of School Banner}}{\textrm{Area of the Sign}}=\frac{1944}{192.61}

Hence The  ratio of the area of the school banner to the area of the sign is 1944:192.61.

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