Answer:
Therefore the inverse function of 
is 
Explanation:
We need to find the inverse of function
Function Inverse definition :
Simplify
Therefore the inverse function of is
Answer:
#include <iostream>
#include<string.h>
using namespace std;
void printCharacter(string name){
for(int i=0;name[i]!='\0';i++){
cout<<name[i]<<endl;
}
}
int main()
{
string name;
cout<<"enter the name: ";
cin>>name;
printCharacter(name);
}
Explanation:
first include the two libraries iostream for input/output and string library for using the string.
then, create the main function and declare the variable type string.
cout instruction is used o display the message on the screen.
cin is used to store the value in the name variable.
after that, call the function. The program control move to the the function. In the function for loop is used to print the character one by one until end of the name.
Answer:
M1 is equal to $ 4 trillion
Explanation:
M1 money supplies are liquid money supplies like cash, checkable deposits, traveler's check etc. It is equal to;
M1= coins and currency in circulation + checkable (demand) deposit + traveler's check.
M2 money supply are less liquid and is equated as;
M2 = M1 + savings deposit + money market fund + certificates of deposit + other time deposits.
Savings = $7 trillion
Checkable deposit = $3 trillion
Money market fund = $1 trillion
Currency = $1 trillion
Certificates of deposit = $1 trillion
M1 = currency + checkable deposit
= $1 + $ 3
= $4 trillion.
Answer:
Un navegador que no existe es firechicken. ja ja
A browser that does not exist is firechicken. lol
Explanation:
Un navegador que no existe es firechicken.
¡Espero que esto ayude! :)
¡Marque el más inteligente!
A browser that does not exist is firechicken.
Hope this helps! :)
Please mark brainliest!
Answer:
def newton(n):
#Define the variables.
t = 0.000001
esti = 1.0
#Calculate the square root
#using newton method.
while True:
esti = (esti + n / esti) / 2
dif = abs(n - esti ** 2)
if dif <= t:
break
#Return the result.
return esti
#Define the main function.
def main():
#Continue until user press enters.
while True:
try:
#Prompt the user for input.
n = int(input("Enter a number (Press Enter to stop):"))
#display the results.
print("newton = %0.15f" % newton(n))
except:
return
#Call the main function.
main()
