The first term (a) is - 18
You add 5 to get to the next term. Or you can solve it by taking any 2 consecutive terms and find their difference.
Formula
d = t4- t3
Givens
t4 = - 3
t3 = - 8
Solution 1
d = t4 - t3 Substitute
d = -3 - ( - 8) Remove the brackets
d = -3 + 8 Combine
d = 5 Difference
Remark
Find the general formula
tn = - a + (n - 1)d Substitute
So term 20 = Example
t20 = -18 + (20 - 1)*5 Combine the inside of the brackets. Remove the brackets
t20 = - 18 + 19*5 Combine 19 and 5
t20 = -18 + 95 "Subtract"
t20 = 77 Answer
Y> or equal 82P/100
P-maximum points of the tests
Answer:
wut
Step-by-step explanation:
He can give at most 2 adult haircuts with the remaining time
<h3>How many adult haircuts at most can he give with the remaining time? </h3>
The inequality is given as:
0.75C + 1.25A <= 7
Also, we have
C = 5
Substitute C = 5 in 0.75C + 1.25A <= 7
0.75 * 5 + 1.25A <= 7
Evaluate the product
3.75 + 1.25A <= 7
Evaluate the like terms
1.25A <= 3.25
Divide by 1.25
A <= 2.6
Rewrite as
A < 3
Hence, he can give at most 2 adult haircuts with the remaining time
Read more about inequalities at:
brainly.com/question/15010638
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<u>Complete question</u>
Horace is a professional hair stylist. Let C represent the number of child haircuts and A represent the number of adult haircuts that Horace can give within 7 hours. 0.75C + 1.25A <= 7
Horace gave 5 child haircuts.
How many adult haircuts at most can he give with the remaining time?
