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Brilliant_brown [7]
2 years ago
14

Someone please help me I’ll give out brainliest please dont answer if you don’t know

Mathematics
1 answer:
Andru [333]2 years ago
5 0

Answer:

subtract 7 from both sides

2x < 7- 7

subtract 7 from 7 to get 0

2x < 0

product of two numbers is < 0 if one is > 0 and the other is < 0. since 2> 0, must be < 0.

x < 0

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What is the approximate circumference of the circle shown below?
Serggg [28]
Hey, there’s no circle for me to look at unfortunately!
4 0
3 years ago
Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +
GenaCL600 [577]

<u>Answer: </u>

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

<u> Solution: </u>

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)  

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3)        ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2)        ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)    

On solving above equation for x    

(x+6) (x+3) =2(x+3) (2x+2)  

x+6 = 4x + 4    

x-4x = 4 – 6

x = \frac{2}{3}

Dimension of pool A

Length = x+6 = (\frac{2}{3}) +6 = 6.667m

Width = x +3 = (\frac{2}{3}) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2(\frac{2}{3}) + 6 = \frac{22}{3} = 7.333m

Width = 2x + 2 = 2(\frac{2}{3}) + 2 = \frac{10}{3} = 3.333m

Verifying the area:

Area of pool A = (\frac{20}{3}) x (\frac{11}{3}) = \frac{220}{9} = 24.44 meter

Area of pool B = (\frac{22}{3}) x (\frac{10}{3}) = \frac{220}{9} = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0
3 years ago
The question is above in the picture​
anzhelika [568]
Yea his answer is right ^^
6 0
3 years ago
Draw a picture to support your work and how many yards did the grasshopper travel after hopping twice
tankabanditka [31]
So the grasshopper traveled 2 yards in each jump
7 0
3 years ago
Can someone help me with this math question WILL GIVE 20 POINTS. By the way it’s not 51.496
GrogVix [38]

Below is the formula for the circumference of a circle

C = 2πr

This question gives us the diameter. To find the radius (r) you would divide the diameter by two like so...

16.4/ 2  = 8.2

Plug what you know into the formula and solve...

π = 3.14

r = 8.2

C = 2(3.14)(8.2)

C = 6.28(8.2)

C = 51.496

In the question it asks to round to the nearest tenth like so...

51.5

Hope this helped!

~Just a girl in love with Shawn Mendes

4 0
3 years ago
Read 2 more answers
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