Kyra multiplied 0.27 by a power of ten and got 2.7. What power of ten did she multiply by?

Mathematics

1 answer:

sveticcg [70]3 years ago

7 0

Answer:

the answer would be A.

Step-by-step explanation:

Look for how many decimal places the decimal moved and thats how many 0's would be in your number

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devlian [24]

Answer/Step-by-step explanation:

✅The y-intercept of the graph of Monday's storm means 0 mm of precipitation was recorded when the tracking started at 0 minutes. The y-intercept is 0 mm.

✅Thursday's Storm has the same y-intercept as the graph of Monday's Storm, which is also 0 mm precipitation at the beginning of the tracking. It has the same meaning as that of the y-intercept of the graph of Monday's Storm.

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3 years ago

Stress at work: In a poll conducted by the General Social Survey, 80% of respondents said that their jobs were sometimes or alwa

Svet_ta [14]

Answer:

a) P=0.019

b) P=0.263

c) P=0.794

Step-by-step explanation:

We assume that the poll gives the population's proportion of respondents said that their jobs were sometimes or always stressful (p=0.8).

Then, a sample of size n=190 is taken.

The sample mean is:

$\mu=np=190*0.8=152$

The sample standard deviation is:

$\sigma=\sqrt{np(1-p)}=\sqrt{190*0.8*0.2}=\sqrt{30.4}=5.514$

The probability that 140 or fewer workers find their jobs stressful is:

$z=(X-\mu)/\sigma=(140.5-152)/5.514=-11.5/5.514=-2.08 \\\\P(X\leq140)=P(X$

Note: a correction for continuity is applied.

The probability that more than 155 workers find their jobs stressful is

$z=(X-\mu)/\sigma=(155.5-152)/5.514=3.5/5.514= 0.635 \\\\P(X>155)=P(X>155.5)=P(z>0.635)=0.263$

The probability that the number of workers who find their jobs stressful is between 145 and 158 inclusive is:

$z_1=(X_1-\mu)/\sigma=(158.5-152)/5.514=6.5/5.514= 1.179\\\\ z_2=(X_2-\mu)/\sigma=(144.5-152)/5.514=-7.5/5.514= -1.360 \\\\ P(145\leq X\leq 158)=P(144.5< X< 158.5)\\\\P(145\leq X\leq 158)=P(X$