3 years ago

What is the degree A. 2 B. 3 C. 6 D. 8

Mathematics

1 answer:

sasho [114]3 years ago

4 0

6 hope i could help good luck

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liberstina [14]

Answer:- The functions f(x) and g(x) are equivalent.

Explanation:-

Given functions:- $f(x)=\sqrt{16^x}$ and $g(x)=\sqrt[3]{64^x }$

Simplify the functions by using law of exponents

$(a^n)^m=a^{nm}$

Thus $f(x)=\sqrt{16^x}=\sqrt{(4^2)^x}=\sqrt{4^{2x}} =\sqrt{(4^x)^2}=4^x$

and $g(x)=\sqrt[3]{64^x}=\sqrt[3]{(4^3)^x}= \sqrt[3]{4^{3x}}= \sqrt[3]{(4^x)^3}=4^x$

⇒f(x)=g(x)

Therefore ,the functions f(x) and g(x) are equivalent.

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Lostsunrise [7]

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It's pretty confusing but I know any of the answers with "c" in it is incorrect. The other options seem correct.

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