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lana66690 [7]
3 years ago
6

Calculate the product of 8/15, 6/5, and 1/3. 

Mathematics
1 answer:
Mariulka [41]3 years ago
5 0
\frac{8}{15} * \frac{6}{5} * \frac{1}{3}

First, I would multiply the last two fractions because they're smaller and easier to work with:

\frac{8}{15} * \frac{6}{5} * \frac{1}{3} = \frac{8}{15} * \frac{6}{15}

Now that we've simplified it, we could multiply these terms and simplify.  An easier method, however, would be to cancel out any common factors among the numerators and denominators before multiplying:

\frac{8}{15} * \frac{6}{15} = \frac{8}{5} * \frac{2}{15}

We can now multiply these terms:

\frac{8}{5} * \frac{2}{15} =  \frac{16}{75}

The <span>product of 8/15, 6/5, and 1/3 is B, 16/75.</span>
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Determine the equation of the circle graphed below. <br><br> ( please help me )
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Answer:

Equation : \\(x+3)^2 + ( y -2)^2 = 36

Step-by-step explanation:

For standard form the circle's equation we need the centre of the circle and the radius.

Step 1: <em><u>Find the centre</u></em>

If the centre is not given find the end points of the diameter

and then find the mid point.

Let the end points of the diameter be : ( - 3 , 8 ) and ( -3 , -4 )

The mid-point of the diameter is :

                        Mid-point = (\frac{-3 + - 3}{2}, \frac{-4+8}{2}) =  (-3, 2)

Therefore, centre of the circle = ( -3 , 2 )

Step 2 : <u>Find radius</u>

<u></u>Radius = \frac{Diameter }{2}<u></u>

Diameter is the distance between the end points ( -3 , 8) and ( -3 , -4 )

That is ,

 Diameter = \sqrt{(-3-(-3))^2 + ( -4 -8)^2}\\

                 = \sqrt{(-3 + 3)^2 + (-12)^2}\\\\=\sqrt{0 + 144}\\\\=12

Therefore ,

       Radius = \frac{12}{2} = 6

Step 3 : <u>Equation of the circle</u>

Standard equation of the circle with centre ( h ,k )

and radius ,r is :

       (x - h)^2+(y -k)^2 = r^2

Therefore, the equation of the circle with centre ( -3, 2)

and radius = 6 is :

    (x - (-3))^2 +  (y - 2)^2 = 6^2\\\\(x + 3)^2 + (y - 2)^2 = 36

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belka [17]

Answer: 1)

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3x - y > 1

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Step-by-step explanation:

7 0
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