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3 years ago

Calculate the product of 8/15, 6/5, and 1/3.

1 answer:

5 0

$\frac{8}{15} * \frac{6}{5} * \frac{1}{3}$

First, I would multiply the last two fractions because they're smaller and easier to work with:

$\frac{8}{15} * \frac{6}{5} * \frac{1}{3} = \frac{8}{15} * \frac{6}{15}$

Now that we've simplified it, we could multiply these terms and simplify. An easier method, however, would be to cancel out any common factors among the numerators and denominators before multiplying:

$\frac{8}{15} * \frac{6}{15} = \frac{8}{5} * \frac{2}{15}$

We can now multiply these terms:

$\frac{8}{5} * \frac{2}{15} = \frac{16}{75}$

The product of 8/15, 6/5, and 1/3 is B, 16/75.

You might be interested in

Suppose that a sample of size 100 is to be drawn from a population with standard deviation L0. a. What is the probability that t

NARA [144]

Answer:

The probability that the sample mean will lie within 2 values of μ is 0.9544.

Step-by-step explanation:

Here

the sample size is given as 100
the standard deviation is 10

The probability that the sample mean lies with 2 of the value of μ is given as

$P(| \bar{X}-\mu|$

Here converting the values in z form gives

$P(-2$

Substituting values

$P(-2$

From z table

$P(z\leq 2)=0.9772\\P(z\leq -2)=0.0228\\P(-2\leq z\leq 2)=P(z\leq 2)-P(z\leq -2)\\P(-2\leq z\leq 2)=0.9772-0.0228\\P(-2\leq z\leq 2)=0.9544\\$

So the probability that the sample mean will lie within 2 values of μ is 0.9544.

5 0

3 years ago

How many even 3-digit positive integers can be written using the digits 1,2,4,7, and 8?

N76 [4]

Looking at the question, we can see we have 5 different numbers that can go in any order.

5 * 4 * 3

The above is basically saying there are 5 different numbers that can be multiplied by 4 other numbers. Those 2 can be multiplied by 3 different ones, leaving us with a 3 digit positive integer.

5 * 4* 3 = 60

4 0

3 years ago

Two planes 2800km apart start flying towards each other at the same time. They meet 3.5 hours later. One plane flies 75km/hour f

uranmaximum [27]

Answer:

yes and good

Step-by-step explanation:

6 0

3 years ago

my brother and i walk the same route every day. my beother takes 40minutes to get to school and i take 30minutes to get to schoo

Goryan [66]

In 1 minute, I walk = 1/30

In 1 minute, My brother walk = 1/40

In T minutes, I walk = T*1/30

My brother walk 8 minute before = T + 8

In 1 minute, My brother walk = (T + 8)*1/40

When these two distances are same, then I will catch him.

T*(1/30) = (T + 8)*(1/40)

30*(T + 8) = 40*T

30*T + 240 = 40*T

240 = 10*T

T = 24 minutes

hence, I will catch him in 24 minutes.

Take 5 instead of 8.

My brother walk 5 minute before = T + 5

In 1 minute, My brother walk = (T + 5)*1/40

When these two distances are same, then I will catch him.

T*(1/30) = (T + 5)*(1/40)

30*(T + 5) = 40*T

30*T + 150 = 40*T

150 = 10*T

T = 15 minutes

Hence, I will catch him in 15 minutes.

6 0

3 years ago

You are about to take the road test for your driver's license. You hear that only 38% of candidates pass the test the first t

OLga [1]

Answer:

Answers may vary but will most likely be close to 2.

Step-by-step explanation

Given:

first test:38%

second test:76%

SIMULATION FIRST TEST

Randomly select a 2-digit number.

If the digit is between 00 and 35 then you passed the test,else you did not pass the test.

SIMULATION SECOND TEST

Randomly select a 2-digit number.

if the digit is between 00 and 75 then you passed the test,else you did not pass the test.

SIMULATION TRIAL

Perform the simulation of the first test.if you did not pass the first test then perform the simulation of the second test.

Record the number of trials needed to pass the first or second test.

Repeat 20 times and take the average of the 20 recorded number of trials

(what is the sum of recorded values divided by 20).

Note:you will most likely obtain a result of about two trials needed.

7 0

3 years ago