Answer:
(a <em><u>s</u></em><em><u>q</u></em><em><u>u</u></em><em><u>a</u></em><em><u>r</u></em><em><u>e</u></em><em><u> </u></em><em><u>+</u></em><em><u>7</u></em><em><u>a</u></em><em><u>+</u></em><em><u>1</u></em><em><u>2</u></em><em><u>)</u></em><em><u> </u></em><em><u>÷</u></em><em><u>(</u></em><em><u>a</u></em><em><u>+</u></em><em><u>3</u></em><em><u>)</u></em>
5 red, 3 blue, 7 white.....total of 15
probability of 1st drawn being red : 5/15 reduces to 1/3
without replacement
probability of 2nd being red : 4/14 reduces to 2/7
probability of both : 1/3 * 2/7 = 2/21 <==
Answer:
t = 4 seconds
Step-by-step explanation:
The height of the projectile after it is launched is given by the function :

t is time in seconds
We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0
So,

The above is a quadratic equation. It can be solved by the formula as follows :

Here, a = -16, b = 32 and c = 128

Neglecting negative value, the projectile will land after 4 seconds.
Answer: 13
Step-by-step explanation:
234grf im doing this for fre points
Answer:
Hence x = y = 2
Step-by-step explanation:
Using the SOH CAH TOA identity
Hypotenuse = 2√2
Opposite = x
theta = 45
Sin theta = opp/hyp
Sin 45 =x/2√2
1/√2 = x/2√2
x = 2√2 * 1/√2
x = 2
To get y we will use the pythagoras theorem;
(2√2)² = x² +y²
(2√2)² = 2²+y²
8 = 4 + y²
y² = 8-4
y² = 4
y = √4
y = 2
Hence x = y = 2