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3 years ago

Find the number of terms and the degree of this polynomial.

Mathematics

1 answer:

dangina [55]3 years ago

5 0

Answer:

Number of terms:3

Degree:2nd degree

Step-by-step explanation:

-5c^2 +8c +2-3

-5c^2 +8c-1

he 2nd degree is the power of 2

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-10=-15+5x heeeeeeeeeeeeeeeeeeeeeeelp me

Allisa [31]

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3 years ago

Clara scored a 79 on her history test what grade does she have to get on her next test so she will have a average of a 83

Airida [17]

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3 years ago

What is the future value of $845 a year for seven years at an interest rate of 11.3 percent? $6,683.95 $6,075.69 $8,343.51 $8,00

k0ka [10]

The future value of cash whose initial value is $845, at the rate of 11.3% for 7 years will be calculated using the compound interest rate, that is:
A=p(1+r/100)^n
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7 0

3 years ago

Read 2 more answers

Find the product.

4vir4ik [10]

Answer :

$6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3 {y}^{3} {z}+3 {y}^{2} {z}^{2}$

Step-by-step explanation :

To find the product of

$3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)$

First we expand the bracket ,

it implies that, we use the expression outside the bracket to multiply individual expressions inside the bracket.

Hence

$3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)$

$= 3 {y}^{2} z(2 {y}^{2} z) + 3 {y}^{2} z(4yz) - 3 {y}^{2} z(y )+3 {y}^{2} z( z)$

we now apply the law of indices

${a}^{m} \times {a}^{n} = {a}^{m+n}$

meaning, when you are multiplying two expressions with the same bases , repeat one of the bases and add the exponents.

Then, simplify to obtain

$= 6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3{y}^{3} {z}+3 {y}^{2} {z}^{2}$

3 0

3 years ago

Which value of x makes the following equation true? <br> 6(x - 1) = -2x + 50

lakkis [162]

Answer:

x=7

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

6(x−1)=−2x+50

(6)(x)+(6)(−1)=−2x+50(Distribute)

6x+−6=−2x+50

6x−6=−2x+50

Step 2: Add 2x to both sides.

6x−6+2x=−2x+50+2x

8x−6=50

Step 3: Add 6 to both sides.

8x−6+6=50+6

8x=56

Step 4: Divide both sides by 8.

8x /8 = 56 /8

x=7

7 0

3 years ago