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Aliun [14]
3 years ago
11

Which value of x makes the following equation true? 6(x - 1) = -2x + 50

Mathematics
1 answer:
lakkis [162]3 years ago
7 0

Answer:

x=7

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

6(x−1)=−2x+50

(6)(x)+(6)(−1)=−2x+50(Distribute)

6x+−6=−2x+50

6x−6=−2x+50

Step 2: Add 2x to both sides.

6x−6+2x=−2x+50+2x

8x−6=50

Step 3: Add 6 to both sides.

8x−6+6=50+6

8x=56

Step 4: Divide both sides by 8.

8x /8 = 56 /8

x=7

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A) 3x+4=21
    3x=21-4
    3x=17
      x=17÷3
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2 years ago
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parallelogram PQRS has PQ=RS=8 cm and diagonal QS= 10 cm. point F is on RS exactly 5 cm from S. let T be the intersection of PF
Doss [256]

<u>Solution-</u>

Given that,

In the parallelogram PQRS has PQ=RS=8 cm and diagonal QS= 10 cm.

Then considering ΔPQT and ΔSTF,

1-    ∠FTS ≅ ∠PTQ            ( ∵ These two are vertical angles)

2-   ∠TFS ≅ ∠TPQ            ( ∵ These two are alternate interior angles)

3-   ∠TSF ≅ ∠TQP            ( ∵ These two are also alternate interior angles)

<em>If the corresponding angles of two triangles are congruent, then they are said to be similar and the corresponding sides are in proportion.</em>

∴ ΔFTS ∼ ΔPTQ, so corresponding side lengths are in proportion.

\Rightarrow \frac{PQ}{FS} =\frac{TQ}{TS} =\frac{TP}{TF}

As QS = TQ + TS = 10 (given)

If TS is x, then TQ will be 10-x. Then putting these values in the equation

\Rightarrow \frac{PQ}{FS} =\frac{TQ}{TS}

\Rightarrow \frac{8}{5} =\frac{10-x}{x}

\Rightarrow x=3.85

∴ So TS = 3.85 cm and TQ is 10-3.85 = 6.15 cm




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3 years ago
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suter [353]
1 and 2 are equivalent
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2 years ago
Kelly deposited $4,205 in an account for 3.5 years. She earned $662.29 in interest. What interest rate did the bank pay her?
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Step-by-step explanation:

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r = 662.29/14717.5

r = 0.045

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Answer:

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