Fraction to tue lowest to 8/16

Can someone give me the answer

Rina8888 [55]

Answer:

A) $y=1.3x+10$

Step-by-step explanation:

1) Plug 2 sets of points into slope formula to find the slope:

$\frac{(16.5-10)}{(5-0)}$

$\frac{6.5}{5}$

2) Write the slope as a decimal:

$m=1.3$

3) Plug the slope and two points into point slope form:

$y-10=1.3(x-0)$

4) Distribute 1.3 to x and 0:

$y-10=1.3x$

5) Add 10 to both sides:

$y=1.3x+10$

6 0

3 years ago

-18=x+12 solve for x

Tanzania [10]

Answer:

x= -30

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

-10x -10y= -10. y=10

stepan [7]

Answer: x = -9

Step-by-step explanation:

-10x - 10y = -10

when y = 10

-10x - 10(10) = -10

-10x - 100 = -10

Add 100 to each side

-10x = 90

Divide each side by -10

x = -9

-10(-9) - 10(10)

90 - 100 = -10

8 0

3 years ago

What Is the line of reflection between pentagons PQRST and P'Q'R'S'T' ?

Sergeu [11.5K]

Answer:

A

Step-by-step explanation:

From the diagram:

P(-4,6)→P'(4,6);
Q(-7,4)→Q'(7,4);
R(-6,1)→R'(6,1);
S(-2,1)→S'(2,1);
T(-1,4)→T'(1,4).

The general rule of this reflection is

(x,y)→(-x,y)

and this is reflection across the y-axis. The y-axis has the equation x=0.

7 0

3 years ago

The Highway Safety Department wants to study the driving habits of individuals. A sample of 37 cars traveling on a particular st

kodGreya [7K]

Answer:

90% confidence interval for the true mean speed of all cars on this particular stretch of highway is [68.9517 miles per hour , 72.4483 miles per hour].

Step-by-step explanation:

We are given that a sample of 37 cars traveling on a particular stretch of highway revealed an average speed of 70.7 miles per hour with a standard deviation of 6.3 miles per hour.

Firstly, the pivotal quantity for 90% confidence interval for the true mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average speed of cars = 70.7 miles per hour

s = sample standard deviation = 6.3 miles per hour

n = sample of cars = 37

$\mu$ = true mean speed

Here for constructing 90% confidence interval we have used One-sample t test statistics as we know don't about population standard deviation.

So, 90% confidence interval for the true mean, $\mu$ is ;

P(-1.688 < $t_3_6$ < 1.688) = 0.90 {As the critical value of t at 36 degree of

freedom are -1.688 & 1.688 with P = 5%}

P(-1.688 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.688) = 0.90

P( $-1.688 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.688 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.688 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.688 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.688 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.688 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $70.7-1.688 \times {\frac{6.3}{\sqrt{37} } }$ , $70.7+1.688 \times {\frac{6.3}{\sqrt{37} } }$ ]

= [68.9517 miles per hour , 72.4483 miles per hour]

Therefore, 90% confidence interval for the true mean speed of all cars on this particular stretch of highway is [68.9517 miles per hour , 72.4483 miles per hour].

The interpretation of the above interval is that we are 90% confident that the true mean speed of all cars will lie between 68.9517 miles per hour and 72.4483 miles per hour.

8 0

3 years ago