To solve for X you need to simplify both sides on the equation
<span><span><span>23</span><span>(<span><span>4x</span>−5</span>)</span></span>=8
</span><span><span><span><span>(<span>23</span>)</span><span>(<span>4x</span>)</span></span>+<span><span>(<span>23</span>)</span><span>(<span>−5</span>)</span></span></span>=8 *</span>Distribute*
<span><span><span><span>8/3</span>x</span>+<span><span>−10/</span>3</span></span>=<span>8
after that you add 10/3 on both sides
</span></span><span><span><span><span><span>8/3</span>x</span>+<span><span>−10/</span>3</span></span>+10/3</span>=<span>8+10/3</span></span><span><span><span>8/3</span>x</span>=<span>34/<span>3
finally multiply 3/8 on both sides
</span></span></span><span><span>(<span>3/8</span>) x </span><span>(<span><span>8/3</span>x</span>)</span></span>=<span><span>(<span>3/8</span>) x </span><span>(<span>34/3</span><span>)
and your answer should be
X= 17/4
</span></span></span>
Answer:
178x12 = 2.136 bro
Step-by-step explanation:
This becomes........
sqrt(72/50) x sqrt(x^16/x^36)= sqrt(36/25) x sqrt(x^-20)= 6/5 x x^-10= 6/(5x^10)
Answer:
the probability is P=0.012 (1.2%)
Step-by-step explanation:
for the random variable X= weight of checked-in luggage, then if X is approximately normal . then the random variable X₂ = weight of N checked-in luggage = ∑ Xi , distributes normally according to the central limit theorem.
Its expected value will be:
μ₂ = ∑ E(Xi) = N*E(Xi) = 121 seats * 68 lbs/seat = 8228 lbs
for N= 121 seats and E(Xi) = 68 lbs/person* 1 person/seat = 68 lbs/seat
the variance will be
σ₂² = ∑ σ² (Xi)= N*σ²(Xi) → σ₂ = σ *√N = 11 lbs/seat *√121 seats = 121 Lbs
then the standard random variable Z
Z= (X₂- μ₂)/σ₂ =
Zlimit= (8500 Lbs - 8228 lbs)/121 Lbs = 2.248
P(Z > 2.248) = 1- P(Z ≤ 2.248) = 1 - 0.988 = 0.012
P(Z > 2.248)= 0.012
then the probability that on a randomly selected full flight, the checked-in luggage capacity will be exceeded is P(Z > 2.248)= 0.012 (1.2%)
Answer:
1. x²
2. xy
3. 2x
4. 4x
5. -4y
6. -8
Step-by-step explanation:
Blank 1:
-x·x=x²
Blank 2:
y·x=xy
Blank 3:
2·x=2x
Blank 4:
-x·-4=4x
Blank 5:
y·-4=-4y
Blank 6:
2·-4=-8
