(Complex Numbers)

Mathematics

1 answer:

marta [7]3 years ago

6 0

Answer:

just saying I'm hosting a google meet if you wanna join lol

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Find the vertex and length of the latus rectum for the parabola. y=-1/2(x-2)^2+8

victus00 [196]

Y = -(1/2)(x-2)² +8
Re write it in standard form:
(y-8) = -1/2(x-2)² ↔ (y-k) = a(x-h)²

This parabola open downward (a = -1/2 <0), with a maximum shown in vertex
The vertex is (h , k) → Vertex(2 , 8)
focus(h, k +c )
a = 1/4c → -1/2 = 1/4c → c = -1/2, hence focus(2, 8-1/2) →focus(2,15/2)

Latus rectum: y-value = 15/2

Replace in the equation y with 15/2→→15/2 = -1/2(x-2)² + 8
Or -1/2(x-2)² +8 -15/2 = 0
Solving this quadratic equation gives x' = 3 and x" = 2, then
Latus rectum = 5

4 0

3 years ago

True or false? Based only on the given information, it is guaranteed that AB CD.

Vladimir [108]

Answer:

Option B is correct that is false.

Step-by-step explanation:

We have been given a figure we need to tell that the two lines are perpendicular

Lines are perpendicular if they meet at right angle.

Line ${\overline{CD}}$ is perpendicular to ${\overline{AB}}$ vice-versa is not true.