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Gelneren [198K]
4 years ago
8

______ is currently the most popular network standard for lans.

Business
1 answer:
natka813 [3]4 years ago
6 0
Ethernet is currently the most popular network standard for LANs. LAN stands for Local Area Network<span> . Ethernet is the most widely used technology to interconnect computers </span><span> in a computer </span>network<span>  within a limited are (building, university, school,...)
</span>Ethernet is a link layer<span> protocol in the </span>TCP/IP stack. It <span> describes how networked devices can format data for transmission to other network devices on the same network segment, and how to put that data out on the network connection. </span>
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carmelita Inc., has the following information available: Costs from Beginning Inventory Costs from Current Period Direct materia
erica [24]

Answer:i dont answer

Explanation:alot of sbhbb b cn n ncn nc nccnx n c zcx nzv zxcv zcv cvzcv zxcbzv CVzxv z xcvzxcv xczv zcvzxcv zxcvzxcv zxcv xzcv zxcvzxcv zcvz cvxcvzxcv zcvxzcv zxvczxcv zx v v v v v zxc v zxcv zc xv zxcv zxcvzxcv zxc zxcv zcv zxcvz xv zxv xc vxcnvcnxv xz v nvn cx cx c xc xc x xvn.

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6 0
3 years ago
Calculate the percentage change in per capita real GDP between 2018 and​ 2019: nothing​%. ​(Enter your response as a percentage
slavikrds [6]

Answer:

3.27% change in per capital  real GDP between 2018 and​ 2019.

Explanation:

The Per capital real of  GDP = Real GDP / Population

In 2016   Per capital real of  GDP:  

$1.21 Billion / 9.68 Million(change billion to million)  

= $1,210 Million / 9.68 Million  

= $125

In 2017  Per capital real of  GDP::

$1.5 Million / 11.62 Million

= $1,500 Million / 11.62 Million  

= $129.09

Therefore Growth in real GDP per capital = ($129.09 / $125) - 1  

= 3.27%

3 0
3 years ago
An investor places $5,000 in an account. The stated annual interest rate is 6% compounded monthly. The value of the account at t
Nostrana [21]

Answer:

$5,983.40

Explanation:

Data provided in the question:

Principle amount = $5,000

Interest rate, r = 6% = 0.06

Time, t = 3 years

Compounded monthly i.e number of periods n = 12

Now,

Final amount = Principle × \left( 1 + \frac{r}{n} \right)^{\Large{n\times t}}

or

Final amount = $5,000 × \left( 1 + \frac{0.06}{12} \right)^{\Large{12\times3}}

or

Final amount = $5,000 × 1.005³⁶

or

Final amount = $5,000 × 1.196

or

Final amount = $5,983.40

7 0
3 years ago
Suppose the supply of I-Pods is QS = 10P, while the demand is QD = 3,000 - 5P. Which of following the statements is true? a. If
olga55 [171]

Answer: If<em><u> the market price of an I-Pod is $220, there will be a surplus of I-Pods.</u></em>

Explanation:

Given :

Q_{S} = 10×P

Q_{D} = 3,000 - 5×P

The equilibrium will occur where supply is equal to demand

i.e. Q_{S} = Q_{D}

10P = 3000 - 5P

15P = 3000

P = $200

∴<u>The equilibrium price is $200</u>

<em><u>Hence, If the market price of an I-Pod is $220, there will be a surplus of I-Pods</u></em>

6 0
3 years ago
You decide to invest in a bond with a 10% coupon paid semi-annually every February 1st and August 1st. The bond is currently sel
Ksenya-84 [330]

The question is missing an important information. 'The bond is currently selling at an asking price of 101.25' In this part there should have been a date at which date the bond was selling at 101.25.

Nevertheless, I will provide with the calculation, if you find out the date, just plug in the value in it and you will get the answer.

The bond price mentioned is $ 101.25 percent of par, which would be $ 1012.5. Since, it is asking for price at May 1st then you know that it has been 89 days since the last semi-annual coupon was paid ( February 1st (28) + March (31) + April (30)  = 89 days.

The missing date (from the question) will be divided by 89 days. The answer will be added to $1012.5.

3 0
3 years ago
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