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sammy [17]
3 years ago
13

Dalia has just enough money to buy either 6 pears and 20 oranges or 12 oranges and 11 pears. A pear costs $ 0.80. How much does

an Orange cost ?
Mathematics
1 answer:
Gelneren [198K]3 years ago
4 0
$6(.80) * 20x =12x* 11(.80)
4.80* 20x = 12x*8.80
        -12x    -12x
$4.80 * 8x = 8.80
-4.80          -4.80
8x=4
/8   /8 
x=$.50 

Proof;
6(.80) + 20(.50) = $14.80
12(.50) + 11(.80) = $14.80
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Now we need standard form.
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y = -6/7x + 22/7

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Graph x + x is less than 2 x
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Answer:

x+x=2x

Step-by-step explanation:

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It takes 5 months and 1 week (21 weeks)


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What is the value of 11−3m, when m = 2?
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3 years ago
Identify the class​ width, class​ midpoints, and class boundaries for the given frequency distribution.
Crank

Answer:

a. Class width=4

b.

Class midpoints

46.5

50.5

54.5

58.5

62.5

66.5

70.5

c.

Class boundaries

44.5-48.5

48.5-52.5

52.5-56.5

57.5-60.5

60.5-64.5

64.5-68.5

68.5-72.5

Step-by-step explanation:

There are total 7 classes in the given frequency distribution. By arranging the frequency distribution into the refine form we get,

Class

Interval frequency

45-48 1

49-52 3

53-56 5

57-60 11

61-64 7

65-68 7

69-72 1

a)

Class width is calculated by taking difference of consecutive two upper class limits or two lower class limits.

Class width=49-45=4

b)

The midpoints of each class is calculated by taking average of upper class limit and lower class limit for each class.

M=\frac{lower class limit+upper class limit}{2}

Class

Interval Midpoints

45-48 \frac{45+48}{2}=46.5

49-52 \frac{49+52}{2}=50.5

53-56 \frac{53+56}{2}=54.5

57-60 \frac{57+60}{2}=58.5

61-64 \frac{61+64}{2}=62.5

65-68 \frac{65+68}{2}=66.5

69-72 \frac{69+72}{2}=70.5

c)

Class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class interval.

Class

Interval Class boundary

45-48 44.5-48.5

49-52 48.5-52.5

53-56 52.5-56.5

57-60 56.5-60.5

61-64 60.5-64.5

65-68 64.5-68.5

69-72 68.5-72.5

7 0
3 years ago
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