We know that
[volume of a cube]=b³---------> b=∛Volume
b------> is the side length of a cube
The top block was 64 cm³------> b1=∛64-------> b1=4 cm
The middle block was 125 cm³------> b2=∛125------> b2=<span>5 cm
T</span>he biggest block was 729 cm³------> b3=√729------> b3=<span>9 cm
[</span><span>the stack of blocks tall]=b1+b2+b3-------> 4+5+9-----> 18 cm
</span><span>
the answer is
</span>the stack of blocks was 18 cm tall<span>
</span>
The solution to your problem is m>-2
Answer: A translation 5 units down followed by a 180-degree counterclockwise rotation about the origin .
Step-by-step explanation:
From the given figure, the coordinates of ΔABC are A(-3,4), B(-3,1), C(-2,1) and the coordinates of ΔA'B'C' are A'(3,1), B'(3,4), C'(2,4).
When, a translation of 5 units down is applied to ΔABC, the coordinates of the image will be
Then applying 180° counterclockwise rotation about the origin, the coordinates of the image will be :-
which are the coordinates of ΔA'B'C'.
Hence, the set of transformations is performed on triangle ABC to form triangle A’B’C’ is " A translation 5 units down followed by a 180-degree counterclockwise rotation about the origin ".
Outcomes in a sample space :)