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krok68 [10]
3 years ago
9

Part of arianna’s earnings are based on a 5% commission rate. At the end of the day arianna earned 14.98 in commission. How much

did arianna sell that day
Mathematics
1 answer:
Katarina [22]3 years ago
7 0

Arianna sold for $ 299.6

<em><u>Solution:</u></em>

Given that, Part of Arianna’s earnings are based on a 5% commission rate

At the end of the day arianna earned 14.98 in commission

Therefore,

Commission earned = $ 14.98

Commission rate = 5 %

Let "x" be the amount that Arianna sell that day

Therefore, according to question,

5 % of amount earned = 14.98

5 % of "x" = 14.98

<em><u>Solve the above equation for "x"</u></em>

5 \% \times x = 14.98\\\\\frac{5}{100} \times x = 14.98\\\\5x = 14.98 \times 100\\\\5x = 1498\\\\Divide\ both\ sides\ of\ equation\ by\ 5\\\\x = 299.6

Thus arianna sold for $ 299.6

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18y4, 27y", and 63y?
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Answer:

9y

Step-by-step explanation:

If you are asking for the Greatest Common Factor [GCF], then here you go. All coefficients are divisible by 9...:

63: 1, 7, 9, 63

27: 1, 3, 9, 27

18: 1, 2, 3, 6, 9, 18

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5 0
3 years ago
An insurance company collected data from a class of high school sophomores on whether or not they have a cell phone and whether
NeX [460]

Answer:

C. Those who have a car tend to have a cell phone.

Step-by-step explanation:

The relative frequency for a data set n is calculated by dividing each frequency x_i by n.

We have a table that relates the use of cars and cell phones.

First, we take from the table the population that has a car.

n = 18

Then, of the students who have a car, 12 have a cell phone and 6 do not have a cell phone.

Then we calculate the relative frequencies f_{x_i} for those who have a cell phone and those who do not.

______________________________________________

Relative frequency   Students with car  n = 18.

-------------------------------------------------- --------------------------------------

C<em>ell phone     No cell phone      Total n</em>

 12/18                    6/18                     18

_______________________________________________

_______________________________________________

Relative frequency   Students with car  n = 18.

-------------------------------------------------- --------------------------------------

C<em>ell phone     No cell phone      Total n</em>

  0.666              0.333                   18

________________________________________________

Most students who have a car also have a cell phone.

Now we calculate the relative frequency for students who do not have a car.

_______________________________________________

Relative frequency  Students without a car  n = 7

-------------------------------------------------- --------------------------------------

<em>Cell phone       No cell phone             Total  n</em>

 2/7                     5/7                          7

_______________________________________________  

_______________________________________________

Relative frequency  Students without a car  n = 7

-------------------------------------------------- --------------------------------------

<em>Cell phone</em>      <em>  No</em> <em>cell phone           Total  n</em>

 0.286                 0.714                              7

_______________________________________________

Most students who do not have a car do not have a cell phone either.

<em>Then these data suggest that. Those who have a car tend to have a cell phone.</em>

Option C

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4 years ago
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2 years ago
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A right triangle's height is 3 times the length of its base. if the area of the triangle is 600, what is the height?
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  <span>a = 1/2 x b x h 

h = 3b 

so 1/2 x b x 3b = (1/2)(3b^2) = 150 

(150 x 2)/3 = b^2 

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b = square root of 100 = 10 

h = 3b = 3 x 10 = 30</span>
3 0
3 years ago
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