1. 7 and -7 are both 7 units away from 0. They are 14 units away from each other. Absolute value helps because rather than 7+(-7) being 0 absolute value makes anything positive so it becomes 7+7=14 to be able to count the units between the two.
2. 5 and -5 are both 5 units away from 0. They are 10 units away from each other. Absolute value helps because rather than 5+(-5) being 0 absolute value makes anything positive so it becomes 5+5=10 to be able to count the units between the two.
3. 2 and -2 are both 2 units away from 0. They are 4 units away from each other. Absolute value helps because rather than 2+(-2) being 0 absolute value makes anything positive so it becomes 2+2=4 to be able to count the units between the two.
Hope that helps
Answer: w = 7, x = 6
Step-by-step explanation: Solve by substitution
W + b = 13
rewrite as b = 13 - w and substitute that value for b in the second equation
6.5w + 2b = 57.5 Then solve for w
6.5w + 2(13-w) = 57.5 . Distribute
6.5w + 26 - 2w = 57.5 . Subtract 26 from both sides. Combine like terms and simplify
6.5w - 2w = 57.5 - 26
4.5w = 31.5 Divide both sides by 4.65
w = 7 . Substitute 7 for w in the first equation and solve for b
7 + b = 13 . Subtract 7 from both sides
b = 6
Answer:
q ≥ 3
Step-by-step explanation:
add 1 to both sides and there you have your answer!
2 ≤ q-1
+1 +1
3 ≤ q
or
q ≥ 3
The answer is A. A(8)=25,000•(1+0.095)8
