Given:
To find:
The f'(y).
Solution:
Chain rule of differentiation:
![[f(g(x))]'=f'(g(x))g'(x)](https://tex.z-dn.net/?f=%5Bf%28g%28x%29%29%5D%27%3Df%27%28g%28x%29%29g%27%28x%29)
Differentiation of exponential:
We have,
Differentiate with respect to y.
Therefore, the differentiation of the given function is .
Answer:
This isn't true.
Step-by-step explanation:
Think of the case a=2, b=3 and c=6. We have that a|b, since 2|6.
We also have that ab=c, since 2*3=6. However, it is NOT true that a|b, as 2 does NOT divide 3. As this you can construct many other examples where a|c and ab=c BUT a does NOT divide b.
Other counterexamples:
a=2, b=5, c=10
a=2, b=7, c=14
a=2, b=11, c=22
a=2, b=13, c=26
Answer:
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Step-by-step explanation:
