Solution:- Given numbers to compare are 512 and 521 .
As they are 3 digit numbers
So, we have to compare hundreds place.
But hundreds are equal in both the numbers with digit 5.
Next we have to compare tens place.
Case 1 :- 1 ten is smaller in 512 than 2 tens in 521 .
So we get the result that,
512 is smaller than 521
or <em> 512 < 521</em>
Case 2:-2 tens is greater in 521 than 1 ten in 512 .
So we get the result that,
521 is greater than 512
or <em> 521 > 512</em>
Answer:
24,25,26
Step-by-step explanation:
Answer:
2.897
Step-by-step explanation:
Let us find the mean and variance for the sample first.
105 104 110 112
114 106 108 109
Mean = sum/8 = 108.5
Variance = 12
Std dev = sq rt of variance = 3.464
Std error = std dev/ sq rt n
since n =8, we get std error = 1.225
Since sample size is small, df =8-1 =7
For 95% confidence intervals, t critical value for two tailed=2.365
Margin of error = std error x t critical = 1.225(2.365)
=2.897
Answer:
The bus travelled 60 miles in 1 hour.
Step-by-step explanation:
To solve this problem we need to calculate the average speed at which the bus travelled. This is given by the distance travelled divided by the time that they took to get there. So we have:
average speed = distance/time
average speed = 360/6
average speed = 60 miles/h
Therefore in 1 hour they travelled 60 miles.
Answer:
X=4
Step-by-step explanation:
2X - 10 = -2
2X = 8
X = 8/2
X = 4
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