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pantera1 [17]
3 years ago
9

Consider the polynomial function (x+3)(x+9)(x-8)=0. which of the following are zeros of the function? Select all that apply. -9

-6 -3 0 3 6 9
Mathematics
1 answer:
Crank3 years ago
6 0
Zeros are:

-3
-9
+8

Looks like only -3 and -9 are offered as answers, though.
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Complete the factored form.<br> 7x² +37x + 10 = (7x + 2)()
Ira Lisetskai [31]
The completed factor is (7x+2) (x+5)

7 0
3 years ago
How does the graph of g(x)=⌈x⌉+7 differ from the graph of f(x)=⌈x⌉?
Lorico [155]
The addition of +7 influences the y values of the graph. Since it is positive, the graph of y=IxI would be moved 7 units upwards. 

Hope I helped :)
8 0
3 years ago
What's this? I don't know
AveGali [126]

Answer:

it's a quadratic formula

Step-by-step explanation:

in the formula, substitute the value of <u>a as 1, b as 2 and c as -8</u>

then, you will get ur answer

3 0
3 years ago
Avery got on the bus at 1:25 P.M. The trip took 74 minutes. Then she walked for 61 minutes to get home.
AnnZ [28]

Answer:

3:40 p.m.

Step-by-step explanation:

Add 74 minutes to 1:25 p.m.; the improperly formed result witll be 1:99 p.m.; to express this properly, add 1 hour to this time and subtract 60 minutes from it:

2:39 p.m. (time at which Avery gets off the bus)

If Avery walked 61 minutes to get home and we want to know what time she arrived, we add 61 minutes to 2:39 p.m., obtaining 2:100 p.m., which must in turn be re-written as 3:40 p.m.

Avery arrived home at 3:40 p.m.

Note:  another way in which to do this problem is to add 74 minutes and 61 minutes, obtaining 135 minutes, and then adding 135 minutes to 1:25 p.m. and making the necessary adjustments to the result:

1:25 p.m. + 135 minutes = 1:160 p.m., or (recognizing that 120 min = 2 hours)

3:40 p.m.

6 0
3 years ago
If the interval (a, ∞) describes all values of x for which the graph of 4/x^2-6x+9 is decreasing, what is the value of a?
harkovskaia [24]

Answer:

a = - 1.1

Step-by-step explanation:

Condition for a single variable function f(x) to be decreasing is f'(x) < 0.

So, in our case, f(x) = \frac{4}{x^{2}} - 6x + 9.

Then, differentiating with respect to x on both sides we get,

f'(x) = 4(- 2)\frac{1}{x^{3}} - 6 < 0

⇒ - \frac{8}{x^{3}} - 6 < 0

⇒ \frac{8}{x^{3}} + 6 > 0

{Dividing both sides with - 1 and hence the inequality sign changes}

⇒ \frac{8}{x^{3}} > - 6

⇒ 8 > - 6x³ {Multiplying both sides with x³}

⇒ 6x³ > - 8 {Interchanging the sides}

⇒ x^{3} > - \frac{8}{6}

⇒ x > - 1.1

Therefore, a = - 1.1. (Answer)

5 0
3 years ago
Read 2 more answers
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