<span>The equation is not quadratic in for because it cannot be written as a second degree polynomial</span>
Lets try 96
4 x ?= 96
? = 96/4
= 24
So we see that 4 times 24 is close to 97.
Question is Incomplete, Complete question is given below.
Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.
Answer:
∆ABC is right angled triangle with right angle at B.
Step-by-step explanation:
Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.
We need to prove that triangle is the right angled triangle.
Let the triangle be denoted by Δ ABC with side as;
AB = (a - 1) cm
BC = (2√ a) cm
CA = (a + 1) cm
Hence,
Now We know that

So;


Now;

Also;

Now We know that




[By Pythagoras theorem]

Hence, 
Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.
This proves that ∆ABC is right angled triangle with right angle at B.
Answer:
76 on second exam, 80 on third exam
Step-by-step explanation:
First, find the total of all 3 test scores by multiplying the average by the number of elements. 81 · 3 = 243.
The first score is 83 so 243 - 83 = 160. 160 is the other two test scores combined.
To find the other 2 scores, divide 160 by 2, which is 80.
The second score is 4 less so it will be 76. The third score is 80.
Answer:
Step-by-step explanation:
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