Therefore the inequality is x≤11
and maximum I can withdraw 11 bills.
Step-by-step explanation:
Given ,
Current balance $320
Minimum balance $100
I could spent =$(320-100) = $220
Let the number of bills be x.
Total amount of x bills = $20x
According to the problem,
20x≤ 220
⇔x ≤
⇔x≤11
Therefore the inequality is x≤11
and maximum I can withdraw 11 bills.
I don’t think they will ever get to see ya anymore but I’m not sure if I can get
Answer:
Step-by-step explanation:
3x2 - y2 = 9.........(1)
x2 + 2y2 = 38......(2)
Let x^2 = a and y^2 = b
:- the two equations becomes
3a - b = 9..........(3)
a + 2b = 38.......(4)
Multiplying (4) by 3
3a + 6b = 114........(5)
Substracting (3) from (5)
3a - 3a + 6b - (-b) = 114 - 9
6b +b = 105
7b = 105
b = 105/7
b = 15
And 3a - b = 9 putting b = 15
3a - 15 = 9
3a = 15+9
3a = 24
a = 24/3
a = 8
And
x^2 = a
x^2 = 8
x = √8
x = √(4×2)
x = 2√2
Also y^2 = b
y^2 = 15
y = √15