All categories

3 years ago

One of the solutions to x^2 - 2x - 15 = 0 is x = -3. What is the other solution

Mathematics

2 answers:

Alex787 [66]3 years ago

8 0

Answer:

x=5

Step-by-step explanation:

You have to factor the equation and the way you do this is to find two numbers that multiply to get -15 and add to get -2 and those numbers are 3 and -5 so the factors are (x+3) and (x-5)

You set them equal to 0 and solve for x

x+3=0 x=-3

x-5=0 x=5

austin2 years ago

0 0

2(x−3) = 2x + 15
how many soultions

You might be interested in

Solve the following inequality algebraically: look at the picture

seraphim [82]

The answer is b -9 < x < 12

8 0

2 years ago

Find f^-1(x) for f(x)=1/x^3 and state whether or not it is a function? (TIMED)

AnnZ [28]

Answer: d

Step-by-step explanation:

8 0

3 years ago

A gallup survey indicated that 72% of 18- to 29-year-olds, if given choice, would prefer to start their own business rather than

Neko [114]

Answer:

The probability that no more than 70% would prefer to start their own business is 0.1423.

Step-by-step explanation:

We are given that a Gallup survey indicated that 72% of 18- to 29-year-olds, if given choice, would prefer to start their own business rather than work for someone else.

Let $\hat p$ = sample proportion of people who prefer to start their own business

The z-score probability distribution for the sample proportion is given by;

Z = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, p = population proportion who would prefer to start their own business = 72%

n = sample of 18-29 year-olds = 600

Now, the probability that no more than 70% would prefer to start their own business is given by = P( $\hat p$ $\leq$ 70%)

P( $\hat p$ $\leq$ 70%) = P( $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ $\leq$ $\frac{0.70-0.72}{\sqrt{\frac{0.70(1-0.70)}{600} } }$ ) = P(Z $\leq$ -1.07) = 1 - P(Z < 1.07)

= 1 - 0.8577 = 0.1423

The above probability is calculated by looking at the value of x = 1.07 in the z table which has an area of 0.8577.

3 0

3 years ago

How many zeros are in the product of any nonzero whole number less than 10 and 500

worty [1.4K]

Answer:

If the non-zero whole number is even, then there are 3 zeroes

If the non-zero whole number is odd, then there are 2 zeroes

Step-by-step explanation:

* Lets explain the information in the problem

- Whole numbers are positive numbers, including zero, without

any decimal or fractional

- Nonzero whole numbers are positive numbers, not including zero

- The non-zero whole numbers less then 10 are:

1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9

- The product of any nonzero whole number less than 10 and 500

means multiply any of nonzero number above by 500

- The number of zeros in the product is equal to the sum of the

number of zeros at the end of each of the factors.

# 1 × 500 = 5 × 100 ⇒ 2 zeros

# 2 × 500 = 2 × 5 × 100 = 10 × 100 ⇒ 3 zeros

# 3 × 500 = 3 × 5 × 100 = 15 × 100 ⇒ 2 zeros

# 4 × 500 = 2 × 2 × 5 × 100 = 2 × 10 × 100 ⇒ 3 zeros

# 5 × 500 = 5 × 5 × 100 = 25 × 100 ⇒ 2 zeroes

# 6 × 500 = 2 × 3 × 5 × 100 = 3 × 10 × 100 ⇒ 3 zeros

# 7 × 500 = 7 × 5 × 100 = 35 × 100 ⇒ 2 zeroes

# 8 × 500 = 2 × 2 × 2 × 5 × 100 = 4 × 10 × 100 ⇒ 3 zeros

# 9 × 500 = 3 × 3 × 5 × 100 = 45 × 100 ⇒ 2 zeros

- From all answers above:

# If the non-zero whole number is even (2 , 4 , 6 , 8), then there are

3 zeros in the product

# If the non-zero whole number is odd (1 , 3 , 5 , 7 , 9), then there are

2 zeros in the product

8 0

3 years ago

Please help i am very confused

Step2247 [10]

Answer:

$\sqrt{80}$

80 is the number in the square root

Step-by-step explanation:

$d = \sqrt{(x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} } \\d = \sqrt{(4-(-4) )^{2} +(5- 1 )^{2} }\\d = \sqrt{(4+4 )^{2} +4^{2}\\d = \sqrt{8^{2} +4^{2} }\\d=\sqrt{64 +16}\\d=\sqrt{80}$

4 0

2 years ago