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Naya [18.7K]
3 years ago
9

Simplify the following expression 8x+9-6x-7

Mathematics
2 answers:
kiruha [24]3 years ago
6 0
1) both 8x and -6x are the same form - they’re just a coefficient with a variable, while 9 and -7 are just plain numbers. move the expression around as shown in the picture: 8x - 6x + 9 - 7. now coefficients with variables are next to each other, while plain numbers are next to each other, making it easier to solve.
2) now solve: 8x - 6x is 2x, and 9 - 7 is 2. now you have 2x + 2, which is the final answer.

i don’t know if i explained it very well, but if you look at the picture you should be fine.
mamaluj [8]3 years ago
4 0
8x + -6x = 2x 2 + 2x
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Express 112 as a product of prime numbers in index form?
alexgriva [62]
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Jessa started with 100 sugar cookies for the Christmas banquet and gave away x cookies. Cooper started with 120 cookies but gave
masya89 [10]

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20 cookies

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5 0
2 years ago
What are the endpoint coordinates for the midsegment of △PQR that is parallel to PQ¯¯¯¯¯?
andriy [413]

Answer:

M(x₄ ,y₄) = (-3.5 , 0.5)  and

N (x₅ ,y₅) = ( -1 , -0.5 )

Step-by-step explanation:

Let the endpoint coordinates for the mid segment of △PQR that is parallel to PQ be

M(x₄ ,y₄) and N(x₅ ,y₅) such that MN || PQ

point P( x₁ , y₁) ≡ ( -3 ,3 )

point Q( x₂ , y₂) ≡ (2 , 1 )

point R( x₂ , y₂) ≡ (-4 , -2)  

To Find:

M(x₄ ,y₄) = ?  and

N (x₅ ,y₅) = ?

Solution:

We have Mid Point Formula as

Mid\ point(x,y)=(\frac{x_{1}+x_{2} }{2}, \frac{y_{1}+y_{2} }{2})

As M is the mid point of PR and N is the mid point of RQ so we will have

Mid\ pointM(x_{4} ,y_{4})=(\frac{x_{1}+x_{3} }{2}, \frac{y_{1}+y_{3} }{2})

Mid\ pointN(x_{5} ,y_{5})=(\frac{x_{2}+x_{3} }{2}, \frac{y_{2}+y_{3} }{2})

Substituting the given value in above equation we get

Mid\ pointM(x_{4} ,y_{4})=(\frac{-3+-4 }{2}, \frac{3+-2} }{2})

∴ Mid\ pointM(x_{4} ,y_{4})=(\frac{-7} }{2}, \frac{1}{2})

∴ Mid\ pointM(x_{4} ,y_{4})=(-3.5, 0.5)

Similarly,

Mid\ pointN(x_{5} ,y_{5})=(\frac{2+-4 }{2}, \frac{1+-2 }{2})

∴ Mid\ pointN(x_{5} ,y_{5})=(\frac{-2 }{2}, \frac{-1}{2})

∴ Mid\ pointN(x_{5} ,y_{5})=(-1, -0.5)

∴ M(x₄ ,y₄) = (-3.5 , 0.5)  and

  N (x₅ ,y₅) = ( -1 , -0.5 )

3 0
3 years ago
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