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diamong [38]
3 years ago
14

What’s the algebraic expression for 8 squared

Mathematics
1 answer:
diamong [38]3 years ago
3 0

Answer:

8^2

Step-by-step explanation:

<u>Step 1:  Convert words into an expression</u>

What’s the algebraic expression for 8 squared

<em>8 squared -> </em>8^2

Answer:  8^2

<u>If needed, solve:</u>

<u />8^2

8 * 8

64

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Use the grid below to name the point at (4,3)
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B

Step-by-step explanation:

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Tessa's class had a math exam <br> What does N(8)&gt;2×N(5) mean
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Answer:

The number of students whose grade was 8 is more than twice the number of students whose grade was 5.

Step-by-step explanation:

N(8) models the number of students whose grades on exam was g.

(The answer is correct, I did it on Khan Academy

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3 years ago
A tire manufacturer knows that 5% of tires contain a defect, and the presence of a defect is independent from tire to tire.
saul85 [17]

The probability that if 5 tires are inspected, exactly 2 have a defect is 0.021

<h3>How to calculate the probability</h3>

The given parameters are:

p = 5\% --- the proportion that contains defect

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r =2 -- the selected sample

The probability is then calculated as:

P(x =r) = ^nC_r * p^r * (1 - p)^{n-r}

So, we have:

P(x =2) = ^5C_2 * (5\%)^2 * (1 - 5\%)^{5-2}

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Hence, the probability that if 5 tires are inspected, exactly 2 have a defect is 0.021

Read more about probabilities at:

brainly.com/question/15246027

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2 years ago
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Find the general solution of the differential equation y′′−14y′+51 y=0. Considered as an independent variable. Use C1, C2, C3, .
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Answer:

Step-by-step explanation:

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3 years ago
What is the simplified form of x plus 4 over x squared minus 3x minus 10⋅x minus 3 over x squared plus x minus 12? (6 points)
melomori [17]

Answer:

The simplified form is 1 over the quantity x plus 2 times the quantity

x minus 5 ⇒ 1/(x+2)(x-5) ⇒ last answer

Step-by-step explanation:

* Lets write the product of the two fraction

∵ \frac{x+4}{x^{2}-3x-10} *\frac{x-3}{x^{2}+x-12}

- At first factorize the denominators

# x² - 3x - 10

∵ x² = x × x ⇒ 1st term in the 1st bracket and 1st term in the

  2nd bracket

∵ -10 = 2 × -5 ⇒ 2nd term in the 1st bracket and 2nd term in the

  2nd bracket

∵ x × - 5 = -5x ⇒ ext-reams

∵ x × 2 = 2x ⇒ means

∵ 2x + -5x = -3x ⇒ middle term

∴ x² - 3x - 10 = (x + 2)(x - 5)

# x² + x - 12

∵ x² = x × x ⇒ 1st term in the 1st bracket and 1st term in the

  2nd bracket

∵ -12 = -3 × 4 ⇒ 2nd term in the 1st bracket and 2nd term in the

  2nd bracket

∵ x × 4 = 4x ⇒ ext-reams

∵ x × -3 = -3x ⇒ means

∵ 4x + -3x = x ⇒ middle term

∴ x² + x - 12 = (x - 3)(x + 4)

* Lets write the fractions after factorization

∴ \frac{x+4}{(x+2)(x-5)}*\frac{x-3}{(x-3)(x+4)}

- lets simplify the fractions by cancel (x - 3) up with (x - 3) down

 and cancel(x + 4) up with (x + 4) down

∴ \frac{1}{(x+2)(x-5)}*1=\frac{1}{(x+2)(x-5)}

* The simplified form is 1 over the quantity x plus 2 times the

  quantity x minus 5

3 0
3 years ago
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