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diamong [38]
3 years ago
14

What’s the algebraic expression for 8 squared

Mathematics
1 answer:
diamong [38]3 years ago
3 0

Answer:

8^2

Step-by-step explanation:

<u>Step 1:  Convert words into an expression</u>

What’s the algebraic expression for 8 squared

<em>8 squared -> </em>8^2

Answer:  8^2

<u>If needed, solve:</u>

<u />8^2

8 * 8

64

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The following back to back stemplot represents the amount a sample of students spent on their last haircut. Because there are si
krek1111 [17]

The 5 - number summary of the distribution obtained from the boxplot is :

  • Minimum = 20
  • Maximum = 85
  • Lower quartile = 35
  • Median = 44
  • Upper quartile = 58
  • Outlier = 100

Firstly, we need to extract the values for the amount spent by females :

20, 25, 25, 35, 37, 38, 39, 43, 45, 46, 50, 53, 60, 70, 85, 100

The five number summary include ;

  • Minimum, lower Quartile, Median, Upper Quartile and Maximum values.

Rearranging the data in ascending order :

20, 25, 25, 35, 37, 38, 39, 43, 45, 46, 50, 53, 60, 70, 85, 100

The boxplot clearly and easily gives the five number summary of the distribution :

  • Minimum = 20 (starting point of the whisker)
  • Lower quartile = 35 (starting point of the box)
  • Median = 44 (vertical line in between the box)
  • Upper quartile = 58 (endpoint of the box)
  • Maximum = 85 (endpoint of the upper whisker).

Outlier :

  • Lower boundary = LOWER QUARTILE - (1.5 × IQR)
  • Upper boundary = UPPER QUARTILE + (1.5 × IQR)
  • IQR = UPPER QUARTILE - LOWER QUARTILE
  • IQR = (58 - 35) = 23

Lower boundary = 35 - (1.5 × 23) = 0.5

Upper boundary = 58 + (1.5 × 23) = 92.5

  • The point denoted by a dot on the boxplot is an outlier = 100

Hence, values lesser than 0.5 or greater than 92.5 are outliers.

Therefore, 100 is an outlier.

Learn more : brainly.com/question/24582786

7 0
3 years ago
Completely simplify the expression 4x+10+6x+2x4x+10+6x+2x
oksian1 [2.3K]
<span>Simplifying 4x + 20 = 6x + -10 Reorder the terms: 20 + 4x = 6x + -10 Reorder the terms: 20 + 4x = -10 + 6x Solving 20 + 4x = -10 + 6x Move all terms containing x to the left, all other terms to the right. Add '-6x' to each side of the equation. 20 + 4x + -6x = -10 + 6x + -6x Combine like terms: 4x + -6x = -2x 20 + -2x = -10 + 6x + -6x Combine like terms: 6x + -6x = 0 20 + -2x = -10 + 0 20 + -2x = -10 Add '-20' to each side of the equation. 20 + -20 + -2x = -10 + -20 Combine like terms: 20 + -20 = 0 0 + -2x = -10 + -20 -2x = -10 + -20 Combine like terms: -10 + -20 = -30 -2x = -30 Divide each side by '-2'. x = 15 Simplifying x = 15</span>
5 0
4 years ago
Read 2 more answers
In Mr. Smith's 7th Hour
tatiyna

binomial(16 + 7, 16) 2^(-(16 + 7)) = ((16 + 7)!)/(16! 7! 2^(16 + 7)) = 245157/8388608 ≈ 0.02922 ≈ 1/34.22

(assuming children are independent and male and female are equally likely)

| probability

less than 16 boys | 0.9534

16 or less boys | 0.9827

more than 16 boys | 0.01734

16 or more boys | 0.04657

fraction of boys | 16/(16 + 7) ≈ 0.695652

fraction of girls | 7/(16 + 7) ≈ 0.304348

expected value | 11.5

standard deviation | 2.398

variance | 5.75

11.5

3 0
3 years ago
Multiply? I don't know how to do this o.o<br><br> (X+4√2) (x-4√2) (x-3i)
Korolek [52]

Answer:

x^{3} -(3i) \; x^{2} -32x + 96 i.

Step-by-step explanation:

Notice that the first two factors are in the form (x-a)(x+a), which is equal to (x^{2} - a^{2}). Start by combining and expanding these two factors:

Let a = 4\sqrt{2}.

a^{2} = 16 \times 2 = 32.

(x + a) (x - a) = x^{2} - a^{2} = x^{2} -32.

This expression can now be expressed as (x^{2} - 32)(x - 3i). i stands the unit imaginary number, where i^{2} = -1. Unless i is raised to a certain power other than 1, it can be treated just like a constant.

Expand this expression using FOIL:

\begin{aligned}&(x^{2} - 32)(x - 3i)\\=&\underbrace{x^{2}\cdot x}_{\verb!F!} +\underbrace{(x^{2})(-3i)}_{\verb!O!} + \underbrace{(-32)x}_{\verb!I!} + \underbrace{(-32)(-3i)}_{\verb!L!}\\=& x^{3} -(3i)x^{2}-32x + 96i \end{aligned}.

6 0
3 years ago
The first three terms of a sequence are given. Round to the nearest thousandth (if
andrey2020 [161]

The 34th term of the sequence 158, 155, 152 ...... is 59

The sequence is as follows:

158, 155, 152 ......

let

a = first term = 158

d = common difference = 155 - 158 = -3

Using Arithmetic progression formula, let's find the 34th term as follows:

aₙ = a + (n - 1)d

a₃₄ = 158 + (34 - 1)-3

a₃₄ = 158 + (33)(-3)

a₃₄ = 158 - 99

a₃₄ = 59

Therefore, the 34th term of the sequence is 59.

learn more about sequence here: brainly.com/question/23251262?referrer=searchResults

3 0
2 years ago
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