SEE ATTACHED IMAGE TO OBSERVE THE GRAPH OF THE FUNCTION.
For this case, the first thing we should see are the cut points with the x axis.
We note that the graph cuts to the x-axis at x = -2
Therefore, x = -2 is the real solution to the polynomial.
Also this function:
x3 + 6x2 + 12x + 8
It can be rewritten as:
(x + 2) ^ 3
From where we conclude that its roots are:
x = -2 (with multiplicity 3)
Answer:
the equation x3 + 6x2 + 12x + 8 = 0 have:
x = -2
As a real solution with multiplicity 3.
For a), this is clearly a given as it is literally to the right of where it says “Given:”
For b), since ON bisects ∠JOH, this means that it splits it into two separate angles - JON and HON, which are similar due to that bisects mean that it splits it equally into two halves
For c), since NO is the same thing as NO, it is equal to itself
For d), since AAS (angle-angle-side) congruence states that if there are two angles that are congruent (proved in a) and b) ) as well as that a side is congruent (proved in c) ), two triangles are congruent
For e), since two triangles are congruent, every side must have one side that it matches up to in the other triangle. As the opposite side of angle H is JO and the opposite side of angle J is OH, and ∠J=∠H, those two are congruent. As JN and HN are the two sides left, they must be congruent.
Feel free to ask further questions!
Answer:
a) linear pair angles: 1&2, 2&3, 3&4, 1&4... etc (any angles that are adjacent, or right next, to each other that add up to be 180 degrees)
b) All linear pair angles are adjacent angles but not all adjacent angles are linear pairs. So pick any linear pair angle you got because they will always be adjacent. (1&2, 2&3, 3&4, 1&4... etc)
c) vertically opposite angles: 1&3, 2&4, 5&7, 6&8, 9&11, 10&12
Step-by-step explanation:
Answer:
<h2>2^7</h2>
Multiply
2^3 by 2^4 by adding the exponents.
Use the power rule
a^m a^n=a^m+n
to combine exponents.
2^3+4
Add 3 and 4.
2^7
Raise 2 to the power of 7.
128
Step-by-step explanation:
Hope it is helpful....
A is 23.4 and b should be k point at 26
