Question

Simplify: 2x^-4/3xy A.) 4y^2 B.) 4x^3y^2/3 C.) 4/x^3y^6 D.) 2/3x^5y

Answer 1

Answer:

$\frac{2x^{-4}}{3xy}=\frac{2}{3x^5y}$

Step-by-step explanation:

Simplify: 2x^-4/3xy

$\frac{2x^{-4}}{3xy}$

To simplify it we use exponential property

$\frac{a^m}{a^n} =a^{m-n}$

we can simplify x

$\frac{x^{-4}}{x^1} =x^{-4-1}=x^{-5}$

$\frac{2x^{-4}}{3xy}=\frac{2x^{-5}}{3y}$

Now we take reciprocal to remove negative. we move x^-5 to the denominator

$\frac{2x^{-4}}{3xy}=\frac{2}{3x^5y}$