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Elina [12.6K]
4 years ago
8

How much work is done by a car engine if the 1200kg car goes 13m up a hill and accelerates from 6 m/s to 7.5m/s?

Physics
1 answer:
kumpel [21]4 years ago
7 0
The work done by the engine is equal to the gravitational potential energy (GPE) put into it.  GPE = mgh
GPE = Work = 1200·9.81·13 = 153,036J
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How many significant figures are there in : (a) 0.000054 (b) 3.001 x 10^5 (c) 5.600
melomori [17]

Answer:

(a) 2 (b) 4 (c) 4

Explanation:

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

Rules for significant figures:

  • Digits from 1 to 9 are always significant and have infinite number of significant figures.
  • All non-zero numbers are always significant. For example: 654, 6.54 and 65.4 all have three significant figures.
  • All zero’s between integers are always significant. For example: 5005, 5.005 and 50.05 all have four significant figures.
  • All zero’s preceding the first integers are never significant. For example: 0.0078 has two significant figures.
  • All zero’s after the decimal point are always significant. For example: 4.500, 45.00 and 450.0 all have four significant figures.
  • All zeroes used solely for spacing the decimal point are not significant. For example : 8000 has one significant figure.

As per question,

0.000054 has 2 significant figures.

3.001 x 10⁵ has 4 significant figures.

5.600 has 4 significant figures.

4 0
3 years ago
A metal rod is 25.000 cm long at 25.0 degrees Celsius. When heated to 102.0
ser-zykov [4K]

Answer:

The coefficient of linear expansion \alpha =2.8\times 10^-5\°C

Explanation:

Given initial temperature t_1=25°C

And final temperature t_2=102°C

Initial length l_1=25.000\ cm

Final length l_2=25.054\ cm

We have to find the coefficient of linear expansion

The coefficient of linear expansion is defined as the change in length per unit original length divide by the change in temperature.

l_2=l_1(1+\alpha (t_2-t_1))\\l_2-l_1=\alpha l_1(t_2-t_1)\\25.054-25.000=25.000(\alpha (102-25))\\0.054=\alpha\times 25(77)\\0.054=\alpha\times1925\\\alpha =\frac{0.054}{1925}=0.000028\C\\\alpha =2.8\times 10^-5

So, \alpha =2.8\times 10^-5\°C

4 0
3 years ago
How many seconds did it take (after starting his descent) for the worker to hit the ground? Answer in units of s.
elena-14-01-66 [18.8K]

Answer:

This question is incomplete

Explanation:

The question is incomplete. However, to determine the time (in seconds) it took a worker to hit the ground from an elevated point. The speed the worker was coming with to the ground and the distance between the elevated point and the ground will have to be considered. Thus the formula to be used here will be

Speed (in meter per second) = distance (in meters) ÷ time (in seconds)

time (in seconds) = distance (in meters) ÷ speed (in meter per seconds)

6 0
3 years ago
How can we measure magnitude of displacement from a v-t curve?​
Ratling [72]

Answer:

The displacement can be calculated by measuring the area of the curve when we move along the t curve. So, that would give the displacement.

Explanation:

4 0
3 years ago
1) Una carga de 10 uC colocada en un campo eléctrico experimenta una fuerza de 60x104N ¿Cuál es la magnitud del campo eléctrico?
Dmitrij [34]

Answer:

pls translate in English

5 0
3 years ago
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