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3 years ago

Another name for temporary worker is

Mathematics

2 answers:

dsp733 years ago

8 0

Another name for temporary worker is contingent employment.

So the correct answer is A.

Hope this helps,

Davinia.

Sholpan [36]3 years ago

3 0

It would be A. (contingent employment)

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A supermarket display consists of boxes of cereal. The bottom row has 23 boxes. Each row has three fewer boxes than the row belo

Vesnalui [34]

Well, I don't know if the following work is exactly what you want but here it goes:

first:23
second: 23-3=20
third: 20-3=17
fourth:17-3=14
fifth: 14-3=11
sixth: 11-3=8

Hope thats what you wanted if not Ill do my best to figure out a different solution. Just comment or private message me For questions. :0

4 0

3 years ago

Read 2 more answers

A rectangle has an area of x^2 -6x -7 and a width of x-7 what’s the length

iogann1982 [59]

Answer:

x+1

Step-by-step explanation:

We know that x^2 -6x-7 is the product of two binomials.

We can solve this two ways, but the easier way is to simply factor rather than divide the area by width.

Two numbers, one of which being -7 allows for the sum of -6 and the product of -7.

Using this information, we can identify the other number is 1, so the length is x+1.

4 0

3 years ago

What is the simplest form of Negative 0.14 in a mixed number

Kazeer [188]

0.14 = 14/100 = 7/50

7 0

3 years ago

Express 1.27 as a percent

pickupchik [31]

To convert from decimal to percent, just multiply the decimal value by 100. In this example we have: 1.27 × 100 = 127% (answer)

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3 years ago

A communications channel transmits the digits 0 and 1. However, due to static, the digit transmitted is incorrectly received wit

m_a_m_a [10]

Answer:

The probability that the message will be wrong when decoded is 0.05792

Step-by-step explanation:

Consider the provided information.

To reduce the chance or error, we transmit 00000 instead of 0 and 11111 instead of 1.

We have 5 bits, message will be corrupt if at least 3 bits are incorrect for the same block.

The digit transmitted is incorrectly received with probability p = 0.2

The probability of receiving a digit correctly is q = 1 - 0.2 = 0.8

We want the probability that the message will be wrong when decoded.

This can be written as:

$P(X\geq3) =P(X=3)+P(X=4)+P(X=5)\\P(X\geq3) =\frac{5!}{3!2!}(0.2)^3(0.8)^{2}+\frac{5!}{4!1!}(0.2)^4(0.8)^{1}+\frac{5!}{5!}(0.2)^5(0.8)^0\\P(X\geq3) =0.05792$

Hence, the probability that the message will be wrong when decoded is 0.05792

4 0

2 years ago