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Anna11 [10]
2 years ago
9

Find the sum of the series √2 - 2 + 2√2 +__+64√2.​

Mathematics
1 answer:
Schach [20]2 years ago
4 0

Step-by-step explanation:

The question is not clear to me

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what is the volume of a cylinder with height of 9 inches and the the radius is 1 inch. round to the nearest cubic inch
poizon [28]

Answer:

Step-by-step explanation:

Volume of cylinder can be calculated by using the formula V= pir^2h

Where r is radius of cylinder and h is the height.

A cylinder with radius 1 inch and height of 9 inch is given.

r=1,h=1,π=3.14.

Substituting the given values :

V=πr2h=π·12·9≈28.27433

Volume of cylinder rounded to nearest tenth is 28.27 cubic inches .

6 0
3 years ago
Help me and dont be mean because i dont know it cuz my little sis was mean earlier
WINSTONCH [101]

Answer:

50 miles per hour

Step-by-step explanation:

50 miles matches up with 1 hour, 100 miles matches up with 2 hours, and so on.

Hope this helps! :)

3 0
3 years ago
Read 2 more answers
A ball is thrown from an initial height of 1 meter with an initial upward velocity of 15m/s. The ball's height h (in meters) aft
lakkis [162]

\bf \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{h}=1+15t-5t^2}\implies \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{6}=1+15t-5t^2}\implies 0=-5+15t-5t^2 \\\\\\ ~~~~~~~~~~~~\textit{using the quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{5}t^2\stackrel{\stackrel{b}{\downarrow }}{-15}t\stackrel{\stackrel{c}{\downarrow }}{+5}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}

\bf t=\cfrac{-(-15)\pm\sqrt{(-15)^2-4(5)(5)}}{2(5)}\implies t=\cfrac{15\pm\sqrt{225-100}}{10} \\\\\\ t=\cfrac{15\pm\sqrt{125}}{10}\implies t=\cfrac{15\pm\sqrt{5^2 \cdot 5}}{10}\implies t=\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\pm ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\sqrt{5}}{\underset{2}{~~\begin{matrix} 10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}

\bf t=\cfrac{3\pm \sqrt{5}}{2}\implies t= \begin{cases} \frac{3+ \sqrt{5}}{2} \approx 2.618\\\\ \frac{3- \sqrt{5}}{2}\approx 0.382 \end{cases}

8 0
3 years ago
Si un triángulo tiene una hipotenusa de 15 cm y un cateto que mide 12 cm, ¿cual es la longitud del otro cateto?
BartSMP [9]

Answer:

   

9cm

Explicación:

El teorema de pitagoras nos dice que la hipotenusa al cuadrado es igual a la suma de los catetos al cuadrado:

c^{2} =a^{2} + b^{2}

Donde c es la hipotenusa y a  y b son los catetos.

Por lo cual, podemos reemplazar c por 15cm y a por 12cm :

15^{2} =12^{2} +b^{2}

Finalmente , debemos resolver la ecuación para b, así que b es igual a :

225=144+b^{2} \\225-144=144+b^{2} -144\\81=b^{2} \\\sqrt{81} =b\\9=b

Por lo tanto, la longitud del otro cateto es 9 cm

3 0
2 years ago
What is 1 1/3 times 1 4/9 in fraction form
nikitadnepr [17]

Answer:

52 / 27

Step-by-step explanation:

3 0
3 years ago
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