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2 years ago

Evaluate the expression for b = 0 and c= -11. bc + b

Mathematics

2 answers:

valina [46]2 years ago

5 0

Answer:

Step-by-step explanation:

The answer would be 0 because (0)(-11)+0=0 since the 0 cancels out the -11 and anything added by 0 is the number.

avanturin [10]2 years ago

3 0

Answer:

If b = 0 and c = -11, all you have to do is plug in the values into bc + b:

Step-by-step explanation:

(0)(-11) + 0 = 0

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2 years ago

What is the average rate of change of f over the interval -1 on a separate sheet of paper and upload the work as a photo. Show a

Anarel [89]

Answer:

Average rate of change for the function $f(x)= x^2-x-1$ over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: $f(x)= x^2-x-1$

The formula used to find average rate of change is:

$Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}$

We have, a = -1 and b = 1

Finding f(b) when b=1

$f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1$

Now, finding f(a), when a= -1

$f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1$

Now, putting values and finding average rate of change

$Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}\\Average\:rate\:of\:change=\frac{f(1)-f(-1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-(1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-1}{1+1}\\Average\:rate\:of\:change=\frac{-2}{2}\\Average\:rate\:of\:change=-1$

So, average rate of change for the function $f(x)= x^2-x-1$ over the interval -1<x<1 is -1

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2 years ago

What is : 3 decreased by 100 ?

Murljashka [212]

3 decreased by 100 is -97. 3-100

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3 years ago

Read 2 more answers