What is 58.58 repeeting converted

In aâ€‹ lottery, 6 numbers are randomly sampled without replacement from the integers 1 to 50. Their order of selection is not i

nlexa [21]

Answer: 0.444225

Step-by-step explanation:

Given : The total number of tickets = 50

Number of tickets are randomly sampled without replacement =6

Since the order of selection is not important , so we use combinations.

Total number of ways to select 6 tickets = $^{50}C_6$

The number of winning tickets = 6

So, number of tickets that are not winning = 50-6=44

Number of ways of selecting zero winning numbers= $^{44}C_{6}$

Now , the probability of holding a ticket that has zero winning numbers out of the 6 numbers selected for the winning ticket out of the 50 possible numbers would be $\dfrac{^{44}C_{6}}{^{50}C_6}$

$=\dfrac{\dfrac{44!}{6!(44-6)!}}{\dfrac{50!}{6!(50-6)!}}\\\\\\=\dfrac{\dfrac{44\times43\times42\times41\times40\times39\times38!}{38!}}{\dfrac{50\times49\times48\times47\times46\times45\times44!}{44!}}\\\\\\=\dfrac{44\times43\times42\times41\times40\times39}{50\times49\times48\times47\times46\times45}\\\\=\dfrac{252109}{567525}\approx0.444225$

Hence, the required probability = 0.444225

8 0

3 years ago

What is the 15th term of the sequence an =<br> -3n+50<br> D. 95

Sauron [17]

Answer:

= 105

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Does the table show a direct proportional relationship? If so, what is the constant of proportionality?

lesantik [10]

Answer:

C. Yes, 3.5.

Step-by-step explanation:

If there is a relationship of direct proportionality for every ordered pair of the table, then the constant of proportionality must the same for every ordered pair. The constant of proportionality ( $k$ ) is described by the following expression:

$k = \frac{y}{x}$ (1)

Where:

$x$ - Input.

$y$ - Output.

If we know that $(x_{1}, y_{1}) = (13, 45.5)$ , $(x_{2}, y_{2}) = (14, 49)$ and $(x_{3}, y_{3}) = (15, 52.5)$ , then the constants of proportionalities of each ordered pair are, respectively:

$k_{1} = \frac{y_{1}}{x_{1}}$

$k_{1} = \frac{45.5}{13}$

$k_{1} = \frac{7}{2}$

$k_{2} = \frac{y_2}{x_2}$

$k_{2} = \frac{49}{14}$

$k_{2} = \frac{7}{2}$

$k_{3} = \frac{y_{3}}{x_{3}}$

$k_{3} = \frac{52.5}{15}$

$k_{3} = \frac{7}{2}$

Since $k_{1} = k_{2} = k_{3}$ , the constant of proportionality is 3.5.

8 0

3 years ago

A ball is thrown from an initial height of 2 feet with an initial upward velocity of 29 ft/s. The ball's height h (in feet) afte

Len [333]

H=14 for this particular instance so:
14=2+29t-16t²
14-2=2-2+29t-16t²
12=29t-16t²
0=-16t²+29t-12
that's as factored as possible so you should use the quadratic formula for the rest and check for extraneous answers

4 0

4 years ago

The sum of three numbers is 54. the third number is 2 times the first. the first number is 6 more than the second. what are the

vaieri [72.5K]

Hello!

To solve this, we will use a system of equations. We will have the numbers be represented by x, y, and z, where x will represent the first, y the second, and z the third.

x+y+z=54
z=2x
x=6+y

We know that x is equal to 6+y. We can plug this into the second equation to find z.

z=12+2y

Now we can plug these y values into the first equation to find y.

6+y+y+12+2y=54
18+4y=54
4y=36
y=9

Now we know the value of y. We can plug this into the equations to find the other values.

x=6+9
x=15

z=15(2)
z=30

Just to check, we will add them all up and see if they equal 64.

15+9+30=54

The first number is 15, the second is 9, and the third is 30.

I hope this helps!

4 0

3 years ago