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Wittaler [7]
3 years ago
12

What is the recursive formula for the sequence? -14, -8, -2, 4, 10,...

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
3 0
You are adding 6 to each number. (N-1)+6, I guess
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60/1 in a equivalent ratio
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60 /1 = 120 /2 = 180 /3

hope it helps
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Please help! I don’t know how to make the square roots equal to each other but I understand the other steps... kind of.
katovenus [111]

Answer:

Step-by-step explanation:

4 0
3 years ago
What is the value of the expression?
Romashka-Z-Leto [24]

Answer: 867

Step-by-step explanation:

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3 years ago
A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u
Kryger [21]

Given: f(x) = \frac{1}{x-2}

           g(x) = \frac{2x+1}{x}

A.)Consider

f(g(x))= f(\frac{2x+1}{x} )

f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}

f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}

f(\frac{2x+1}{x} )=\frac{x}{1}

f(\frac{2x+1}{x} )=1

Also,

g(f(x))= g(\frac{1}{x-2} )

g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{x }{1}

g(\frac{1}{x-2} )= x


Since, f(g(x))=g(f(x))=x

Therefore, both functions are inverses of each other.


B.

For the Composition function f(g(x)) = f(\frac{2x+1}{x} )=x

Since, the function f(g(x)) is not defined for x=0.

Therefore, the domain is (-\infty,0)\cup(0,\infty)


For the Composition function g(f(x)) =g(\frac{1}{x-2} )=x

Since, the function g(f(x)) is not defined for x=2.

Therefore, the domain is (-\infty,2)\cup(2,\infty)



8 0
3 years ago
If f(x) = 5x - 11, find f(-2m + 5)
sukhopar [10]

f(-2m + 5)=5(-2m+5)-11=-10m+25-11=-10m+14

8 0
3 years ago
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