Ask question

Ask question

All categories

3 years ago

12

What is the recursive formula for the sequence? -14, -8, -2, 4, 10,...

1 answer:

FinnZ [79.3K]3 years ago

3 0

You are adding 6 to each number. (N-1)+6, I guess

You might be interested in

60/1 in a equivalent ratio

Elena-2011 [213]

60 /1 = 120 /2 = 180 /3

hope it helps

8 0

3 years ago

Read 2 more answers

Please help! I don’t know how to make the square roots equal to each other but I understand the other steps... kind of.

katovenus [111]

Answer:

Step-by-step explanation:

4 0

3 years ago

What is the value of the expression?

Romashka-Z-Leto [24]

Answer: 867

Step-by-step explanation:

You subtract what is in the parentheses then add them together

7 0

3 years ago

A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u

Kryger [21]

Given: $f(x) = \frac{1}{x-2}$

$g(x) = \frac{2x+1}{x}$

A.)Consider

$f(g(x))= f(\frac{2x+1}{x} )$

$f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}$

$f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}$

$f(\frac{2x+1}{x} )=\frac{x}{1}$

$f(\frac{2x+1}{x} )=1$

Also,

$g(f(x))= g(\frac{1}{x-2} )$

$g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{x }{1}$

$g(\frac{1}{x-2} )= x$

Since, $f(g(x))=g(f(x))=x$

Therefore, both functions are inverses of each other.

B.

For the Composition function $f(g(x)) = f(\frac{2x+1}{x} )=x$

Since, the function $f(g(x))$ is not defined for $x=0$ .

Therefore, the domain is $(-\infty,0)\cup(0,\infty)$

For the Composition function $g(f(x)) =g(\frac{1}{x-2} )=x$

Since, the function $g(f(x))$ is not defined for $x=2$ .

Therefore, the domain is $(-\infty,2)\cup(2,\infty)$

8 0

3 years ago

If f(x) = 5x - 11, find f(-2m + 5)

sukhopar [10]

$f(-2m + 5)=5(-2m+5)-11=-10m+25-11=-10m+14$

8 0

3 years ago