Answer:
4 units ...................
I like the idea that life is for fun. Just chase your dreams~
Answer: 13
Step-by-step explanation:
234grf im doing this for fre points
Answer:
please mark me as brainlist please
Step-by-step explanation:
we know, ∠BGA = 90
In right angled triangle BGA
AB = 12 cm (diameter of circle)
⇒ (AB)2 = (AG)2 + (BG)2
⇒ 122 = 82 + (BG)2
⇒ BG = 4√5
In right angled triangle BCG
Let CG be x cm.
⇒ (BC)2 = (CG)2 + (BG)2
⇒ (BC)2 = x2 + (4√5)2 ----(1)
As we know,
⇒ (BC)2 = CG × CA ----(2)
From equation (1) and equation (2)
⇒ x2 + (4√5)2 = x × (x + 8)
⇒ x2 + (4√5)2 = x2 + 8x
⇒ 8x = 80
⇒ x = 10 cm
From equation (2)
⇒ (BC)2 = CG × CA
⇒ (BC)2 = 10 × 18 = 180
⇒ BC = √180 = 6√5
6 × 5 = 30
To determine what the line looks like, simply change it to y = mx + b form. Then simply either make a table of values. And substitute any points into the equation and obtain points to plot on the graph. Or you can simply plot the graph by using the slope of the equation.
Y = 8 - 6x/2
Y = 4 - 3x
Y = -3x + 4.
This would be the rearranged equation.
