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3 years ago

Solve for m2m = -6n -5; n = 1, 2 ,3

1 answer:

8 0

Substitute with the value of n in the equation to get m as follows:
at n=1:
2m=-6(1)-5=-6-5=-11
m = -11/2
at n=2:
2m=-6(2)-5=-12-5=-17
m = -17/2
at n=3:
2m=-6(3)-5=-18-5=-23
m = -23/2

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A sandbox has an area of 10 2/3 square feet, and the length is 1/4 feet. What is the width of the sandbox?

AlekseyPX

Answer:

The width of the sandbox is $42\frac{2}{3} \ ft$ .

Step-by-step explanation:

Given,

Area of the sandbox = $10\frac{2}{3}=\frac{32}{3}\ ft^2$

Length = $\frac{1}{4}\ ft$

Solution,

Let the width of the sandbox be 'w'.

Since the sandbox is in shape of rectangle.

So we use the formula of area of rectangle.

$Area = Length\times Width$

On substituting the given values, we get;

$\frac{1}{4}\times w=\frac{32}{3}\\$

By cross multiplication method, we get;

$w=\frac{32\times4}{3\times 1} =\frac{128}{3} =42\frac{2}{3} \ ft$

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3 years ago

Jim is building a model of a square pyramid for a class project. The side length of the square base is 20 inches and the slant h

Brums [2.3K]

Answer:

$SA = 920 inches^{2}$

Step-by-step explanation:

Given Data:

Slant height of square pyramid = l = 13 inches

Base edge of square pyramid = s = 20 inches

To Find Out:

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3 years ago

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Answer:

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3 years ago

Read 2 more answers