Answer:
The correct option is O B'
Step-by-step explanation:
We have a quadrilateral with vertices A, B, C and D. A line of reflection is drawn so that A is 6 units away from the line, B is 4 units away from the line, C is 7 units away from the line and D is 9 units away from the line.
Now we perform the reflection and we obtain a new quadrilateral A'B'C'D'.
In order to apply the reflection to the original quadrilateral ABCD, we perform the reflection to all of its points, particularly to its vertices.
Wherever we have a point X and a line of reflection L and we perform the reflection, the new point X' will keep its original distance from the line of reflection (this is an important concept in order to understand the exercise).
I will attach a drawing with an example.
Finally, we only have to look at the vertices and its original distances to answer the question.
The vertice that is closest to the line of reflection is B (the distance is 4 units). We answer O B'
0.6 divided by 12.9.
0.6 is outside the house for the divide then inside the house is 12.6
then you move your decimal point over 1 place so its 06 divide by 126.
after that 6 goes into 12 twice then your have a remainder of 09 then 6 goes into 9 once, our remainder is 3, then you put a 0 at the end of the decimal point of the 126. after that you bring down your zero and 6 goes into 30 five times.
Answer 21.5