Answer:
Ello, estoy aquí para ayudar, pero hablo español, con suerte, entenderás que lo estoy intentando.
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Step-by-step explanation:
Have you learned matrices yet? I'm going to use that to solve these, please refer to the photos.
I solved the system by using a matrix calculation. The work always needs to be shown and you do that by setting up the matrix like in the first photo and also writing out all your equations. In a TI calculator, to do this you press 2ND-X^-1,GO TO EDIT - [A] - 3×4- now enter the coefficient of the system of equations variables. NOW 2ND MODE- 2ND-X^-1 -GO TO MATH- ALPHA APPS
Now, if you don't know this you may be confuse so after rref([A]) was enter a matrix came up with [1 0 0 -21] in the top row this means x equal -21. So, the next row is y and it came out as [0 1 0 46] so y equals 46 and I'm going to let you figure out what z is by looking at the matrix.
SO... X=-21 Y=46 and Z=-10
Let's Test it
Answer:
The correct answer is third option. 994
Step-by-step explanation:
<u>Points to remember</u>
Volume of cylinder = πr²h
Where 'r' is the radius and 'h' is the height of cylinder
From the given question we get the cylinder height and radius
The height h = 3 times the diameter of one ball
= 3 * 7.5 = 22.5 cm
Radius = half of the diameter of a ball
= 7.5/2 = 3.75 cm
<u>To find the volume of cylinder</u>
Volume of cylinder = πr²h
= 3.14 * 3.75² * 22.5
= 993.515 ≈ 994
The correct answer is third option. 994
The height of the rocket is found in terms of the angle as
.. h/(3 mi) = tan(θ)
.. h = (3 mi)*tan(θ)
Then the rate of change of height (vertical velocity) is
.. h' = (3 mi)*sec(θ)^2*θ'
.. h' = (3 mi)*4*(1.5 rad/min)
.. h' = 18 mi/min
The rocket's velocity is 18 miles per minute at that moment.