3 years ago

How do we use the Pythagoras theorem in "everyday life".

1 answer:

5 0

I use it all the time, but as my profession is engineering, mathematics is integral in my everyday life. I usually do it when evaluating for the magnitude of vector force components. Usually in 2D space, so Pythagorean theorem is quite useful.

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Divide using synthetic division (3y^4-13y^3+12y^2-33y+9)/(y-4)

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Twice the sum of x and 5

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I believe it would be x+5^2

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3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%2832%29%5E%7B1%2F5%7D" id="TexFormula1" title="(32)^{1/5}" alt="(32)^{1/5}" align="absmiddle"

lorasvet [3.4K]

Answer:

Step-by-step explanation:

${32}^{ \frac{1}{5} }$

$= \sqrt[5]{32}$

$= \sqrt[5]{2 \times 2 \times 2 \times 2 \times 2}$

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2 years ago

What is the value of cos(150°)?

baherus [9]

ANSWER

$-\frac{\sqrt[]{3}}{2}$

EXPLANATION

Given

$\begin{gathered} \cos \text{ 150} \\ \end{gathered}$

We can find cos 150 by using

$\begin{gathered} \cos (180-\theta)=-\cos \theta \\ \Rightarrow\cos (180-\theta) \\ =-\cos 30 \end{gathered}$

recall that

$\begin{gathered} \cos 30=\frac{\sqrt[]{3}}{2} \\ \end{gathered}$

Hence,

$\begin{gathered} \cos 150=-\cos 30 \\ =-\frac{\sqrt[]{3}}{2} \\ \end{gathered}$

Therefore, the value of cos 150 is

$-\frac{\sqrt[]{3}}{2}$

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