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2 years ago

If you multiply 5(2x+3+4y), the answer is ______

Mathematics

2 answers:

natima [27]2 years ago

8 0

C-10x+15+20y ,multiply the 5 with each number inside of the parenthesis

Volgvan2 years ago

6 0

Answer:

You don't even need to do the whole question. Just look at 5 times 2x. which is 10x then u get your answer

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Write the expression without using exponents (-2y)^4

JulsSmile [24]

Answer:

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Step-by-step explanation:

Getting rid of exponents:

(-2y)^4 =
(-2)^4*y^4 =
16yyyy

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Answer:

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Step-by-step explanation:

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(-5+3)+(x+10x)

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-2+11x

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2 years ago

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Law of radicals

andrey2020 [161]

Answer:

1) $\sqrt{x^7}=x^{\frac{7}{2}$

2) $\sqrt[3]{y^5}=y^{\frac{5}{3}$

3) $\sqrt[5]{a^{12}}=a^{\frac{12}{5} }$

4) $\sqrt[4]{z^{9}}=z^\frac{9}{4}$

Step-by-step explanation:

1) $\sqrt{x^7}$

We know that $\sqrt{x}=x^{\frac{1}{2}$

So, $\sqrt{x^7}=x^{\frac{7}{2}$

2) $\sqrt[3]{y^5}$

We know that $\sqrt[3]{x}=x^{\frac{1}{3}$

So, $\sqrt[3]{y^5}=y^{\frac{5}{3}$

3) $\sqrt[5]{a^{12}}$

We know that $\sqrt[5]{x}=x^{\frac{1}{5}$

So, $\sqrt[5]{a^{12}}=a^{\frac{12}{5} }$

4) $\sqrt[4]{z^{9}}$

We know that $\sqrt[4]{x}=x^{\frac{1}{4}$

So, $\sqrt[4]{z^{9}}=z^\frac{9}{4}$

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3 years ago