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GaryK [48]
3 years ago
10

Find the surface area of the cylinder to the nearest whole number. The figure is not drawn to

Mathematics
1 answer:
Anettt [7]3 years ago
5 0

Answer:

correct option is 2187

Total surface area is  2,185.44  square inches.

lateral surface area is  640.56 square inches

Step-by-step explanation:

Given

radius of cylinder = 12 inches

height of cylinder = 17 inches

we will us value of pi as 3.14

surface area for cylinder consist of two part

1. lateral surface area which is gven by 2\pi rl

where r is radius of cylinder and l is height of cylinder

Thus, lateral surface area for given cylinder is

2\pi rl\\ =>2* 3.14*12*17\\=> 1281.12

Thus,  lateral surface area for given cylinder is  1281.12 square inches.

_________________________________

second part of surface area is area of two base (upper and lower) of cylinder.

area of base is given by area of circle \pi r^2

area \ of  \base = \pi r^2 = 3.14*12^2\\=>area \ of  \base =  3.14*144 = 452.16

This, area of base is for one base of cylinder

since there are 2 base

area of both base will be = 2* area of one base

                                      = 2*452.16 = 904.32.

Thus, area of base is 904.32 sq. in.

_______________________________________

Total surface area of cylinder = area of two base+ lateral surface area of cylinder = 1281.12 square inches + 904.32 square inches

                  = 2,185.44  square inches.

Thus, total surface area is  2,185.44  square inches.

lateral surface area is  640.56 square inches

but option which is closest to calculated value is  2187.

Thus, correct option is 2187

___________________________________________

Note: this problem can be directly solved using formula

total surface area for cylinder = 2\pi r^2 + 2\pi rl

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By geometry,
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A line goes through the points (5, -1) and (7, -5). What is a possible equation to a new line that is perpendicular?
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<em>Ok, so you are given an equation in standard form, 5x+4y=2, and a point, (7, 5). You are being asked to write the equation for a line that is parallel to the equation in standard from, and that includes the point (7, 5).  </em>

<em> </em>

<em> </em>

<em> </em>

<em>First, let's start by finding the slope of your new line. We know that it needs to have the same slope as 5x+4y=2, because parallel lines have the same slopes. To do that, we need to put the equation into slope-intercept form (y=mx+b), which means we need to isolate the "y."  </em>

<em> </em>

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<em>  5x+4y=2 </em>

<em> </em>

<em>-5x     -5x  (subtract 5x from both sides to move it to the right side of your equation) </em>

<em> </em>

<em>4y = 2 - 5x </em>

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<em> </em>

<em>y = (1/2) - (5/4)x  ... I suggest leaving your slope as a fraction. </em>

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<em>Now, we know that our slope, m , is going to be -(5/4).  </em>

<em> </em>

<em> </em>

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<em>Next, we are going to use our slope, -(5/4), and point, (7, 5), to find the b-value (y-intercept) of your new line. Let's plug in what we know: </em>

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<em>y = 5 </em>

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<em>m = -(5/4) </em>

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<em> </em>

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<em>y=mx+b </em>

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<em>20/4 = -(35/4) + b -> I converted 5 into a faction with a denominator of 4 by multiplying by (4/4) </em>

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<em>Answer:  </em>

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<em>m = -(5/4) </em>

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